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love history [14]
2 years ago
14

Please answer ASAP!!!! Will give branliest!!!!

Mathematics
2 answers:
Nataly [62]2 years ago
7 0

We know that the perimeter of a rectangle is 2l+2w

24=2y+2x

Subtract 2x on both sides (we are isolating y)

24-2x=2y

Divide 2 on both sides

Therefore, y=12-x

Some possible values using this equation..

y=8

x=4

Hope this helped :)

RideAnS [48]2 years ago
5 0

If the width is x, we count x twice since there are two widths in a rectangle. The perimeter is: 24 = 2x + 2y.

That means that 2y = 24 - 2x

and

y = 12 - x

x obviously has to be greater than 0, but to make sure that y is not zero and positive, we look at the equation y = 12 - x to determine possible values of x. The greatest possible value of x is 11, so: 0 < x < 11.

If we look back at our equation: 24 = 2x + 2y, we see that we can write it as:

2x = 24 - 2y or

x = 12 - y

We can use the same explanation we used to find the possible values of x to find the possible values of y: 0 < y < 11

So, the three answers are:

y = 12 - x

width is: 0 < x < 11

length is: 0 < y < 11

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Answer:

(8, -7)

Step-by-step explanation:

well since it flip over the x-axis only, the 8 stays the same, however, the 7 flips completely to the second quadrant and becomes -7.

Hope this helped and have a amazing day.

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Simplify the radical
olga55 [171]

Answer:

Step-by-step explanation:

\sqrt[3]{54c}=\sqrt[3]{3*3*3*2c} =3\sqrt[3]{2c}

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Anyone got answers to this? Need help asap it’s due tomorrow!!
umka2103 [35]

The figure on the left side shows the water level is at the 0.5 liter mark, ie half a liter.

1 liter = 1000 mL

0.5*1 liter = 0.5*1000 mL

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If you poured all the water into the jug on the right (without spilling), then the water level should reach the 500 mL mark. This is the small tickmark exactly halfway between the 400 and 600.

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2 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
VashaNatasha [74]

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

8 0
2 years ago
Graded Assignment Unit Test, Part 2: Basic Geometric Shapes Answer the questions below. When you are finished, submit this assig
AfilCa [17]

Answer:

In case (a) car makes 105° turn.

In case (b) car makes 75° turn.

In case (c) car makes 105° turn.

Step-by-step explanation:

Figure is redrawn To explain properly (in attachment)

Given : streets are parallel means \overline{AB} ║ \overline{CD},

             AB - 4th street , CD - 3rd street and XY - King Ave.

            ∠XLA = 75°

To find : (a) ∠XLB

              (b) ∠LMD (left onto 3rd streat means left of car)

              (c) ∠YMD (right means right side of car)

∠XLB + ∠XLA = 180° (Linear Pair = 2 adjacent angles are  

                                     supplementary)

∠XLB + 75° = 180°

∠XLB  = 180 - 75

∠XLB = 105°

∴ In case (a) car makes 105° turn.

∠LMD = ∠XLA = 75° (Corresponding angles of parallel lines are equal)

∠LMD = 75°

∴ In case (b) car makes 75° turn.

∠YMD + ∠LMD = 180° (Linear Pair = 2 adjacent angles are

                                       supplementary)

∠YMD + 75° = 180°

∠YMD = 180 - 75

∠YMD = 105°

∴In case (c) car makes 105° turn.

8 0
3 years ago
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