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3 years ago

29*47 in expanded algorithm

Mathematics

2 answers:

Tresset [83]3 years ago

7 0

Hey there! :D

So for this problem, we would do 20+9 x 40 + 7 which equals 1,363.

Hope it helps! :D

Kamila [148]3 years ago

6 0

20+9 x 40 + 7 which equals 1,363.

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I need help SHOW YOUR WORK

earnstyle [38]

Answer:

$F)\displaystyle \: 100\pi{ x}^{8} {y}^{2} {z}^{ 6}$

Step-by-step explanation:

we are given r and the formula

we want to find the surface area of the shpare with the given r

to do so

we need our algebra skills

substitute the value of r:

$\displaystyle \: S = 4\pi( {5x}^{4} y {z}^{ 3} {)}^{2}$

recall law of exponent

$\displaystyle \: ({x}^{m} {)}^{n} \iff \: {x}^{mn}$

to simplify:

$\displaystyle \: S = 4\pi({ {5}^{2} x}^{4 \times 2} {y}^{1 \times 2} {z}^{ 3 \times 2} )$

simplify multiplication:

$\displaystyle \: S = 4\pi({ 25x}^{8} {y}^{2} {z}^{ 6} )$

distribute:

$\displaystyle \: S = 100\pi{ x}^{8} {y}^{2} {z}^{ 6}$

hence our answer is F

5 0

2 years ago

A padlock has a four-digit code that includes digits from 0 to 9, inclusive. What is the probability that the code does not cons

Eduardwww [97]

Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.

4 0

3 years ago

Read 2 more answers

The first picture is the graph (already answered) and the second is the next

Nastasia [14]

Answer:

a) 100/15 = 6.6667 = 6 2/3

b) C = T( 6 2/3)

= T (6 + 2/3)

C = 1T x 6 2/3

= 6 2/3 T

We can show T as time at end of equation or start of brackets