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4 years ago

Why do we call meteors shooting stars?

Chemistry

1 answer:

zlopas [31]4 years ago

6 0

They burn up and cause it to look like shooting stars

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The pencil is material or mixture ?please help

disa [49]

Answer:

mixture

Explanation:

6 0

3 years ago

When potassium carbonate and calcium chromate are mixed, which of the following will pass through a filter?

aliina [53]

Calcium carbonate will be formed which is insoluble in water.

The answer is a) K and CrO4 only.

8 0

3 years ago

The solubility of N2in blood at 37°C and at a partial pressure of 0.80 atm is 5.6 × 10−4mol/L. A deep-sea diver breathes compres

Luda [366]

Solution :

According to Henry's law of solubility, we have c = kp

Henry's law constant, $k=\frac{c}{p}$

$=\frac{0.00056}{0.80}$

= 0.0007 mol/L.atm

When the pressure is = 4 atm

The solubility is c = 0.0007 mol/(L.atm) x 4 atm

= 0.0028 mol/L

Therefore, in a 5 liter of blood, the moles of nitrogen dissolved

= 0.0028 x 5

= 0.014 moles

At the surface, the solubility is = 0.00056 mol/L

So the moles of the nitrogen dissolved = 5 x 0.00056

= 0.0028 moles

Therefore, the number of moles of nitrogen released = 0.014 - 0.0028

= 0.0112 moles

Given total pressure = 1 atm

Temperature = 37 degree C

= 37 + 273

= 310 K

R = $0.0821\ L -atm/ mol.K$

Therefore, volume of the nitrogen is

$V=\frac{nRT}{P}$

$V=\frac{0.0112 \times 0.0821 \times 310}{1}$

= 0.285 L

5 0

3 years ago

An electrically neutral atom consists of 15 neutrons, 13 electrons, and a number

Anna71 [15]

Answer:c

Explanation: it states that the atom is neutral, meaning the number of electrons and protons are the same. so if there are 13 electrons, there are 13 protons. And the mass number is neutrons plus protons. So 13+15 is 28

5 0

3 years ago

In aqueous solution the Hg2+ ion forms a complex with four iodide anions. Write the formation constant expression for the equili

lukranit [14]

Answer:

Following are the solution to the given question:

Explanation:

In the aqueous solution of $Hg^{2+}$ ion is used to represent a $[Hg(H_2O)_4]^{2+}$ .

It is used to form a complex with iodide ions as $[Hgl_4]^{2-}$ .

Conversion reaction:

$[Hg(H_2O)_4]^{2+} +4I^{-} \to [HgI_4]^{2-}+4H_20$

Following are the formation constants:

$k_f=\frac{[HgI_4]^{2-}}{[Hg(H_2O)_4]^{2+} [I^{-}]^4}$

Following are the first step to the conversion:

$[Hg(H_2O)_4]^{2+} +I^{-} \to [HgI(H_2O)_3]^{+}+H_20$

8 0

4 years ago