Answer:
n C2H5OH = 0.2496 mol
Explanation:
- moles (n) = mass / molecular weight
∴ m C2H5OH = 11.5 g
∴ Mw C2H5OH = (2)(12.011) + (6)(1.00794) + 15.9994 = 46.069 g/mol
⇒ n C2H5OH = (11.5 g)/(46.069 g/mol) = 0.2496 mol C2H5OH
Answer:
the first one. a homogeneous mixture.
Explanation:
hope this helps :)
The values of the changes are
ΔH = 46.44kJ
Δu = 43.34Kj
ΔS = 126.6 J/K
<h3>How to find change in H</h3>
= 1 mol + 75.3 (100 + 273) - 25 + 273 + 1 * 40.79
= 5.6475 + 40.79
= 46.44kJ
<h3>How to find change in S</h3>
1 mol + 75.3 x ln 373/298 + 1 mol x 40.79
= 0.1263
ΔS = 126.6 J/K
<h3>How to find the change in U</h3>
46.44 - 0.00831 * 373
= 43.34Kj
Read more on molar heat here:
brainly.com/question/13439286
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NH3 has three covalent bonds
H-N-H
H
h2s has 2
ch4 has 4
co has 2
co2 has 4
Answer:
Explanation:
Hello,
In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:
Clearly, the concentrated solution is 7.00M and the diluted solution is unknown, thus, the concentration of the diluted solution after the dilution to 100 mL is:
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