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2 years ago

The [-oh) in a sample of egg whites is 6.3 x 10-7 m. what is the [h3o+] in theseegg whites?

Chemistry

1 answer:

Kamila [148]2 years ago

7 0

The hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.

<h3>How to calculate [H3O+]?</h3>

The hydrogen ion concentration of a solution can be calculated as follows:

pOH = - log [OH-]

pOH = - log [6.3 × 10-⁷M]

pOH = - [-6.2]

pOH = 6.2

Since pOH + pH = 14

pH = 14 - 6.2

pH = 7.8

pH = - log [H3O+]

7.8 = - log [H3O+]

[H3O+] = 10-⁷:⁸

[H3O+] = 1.5 × 10-⁸M

Therefore, the hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.

Learn more about hydrogen ion concentration at: brainly.com/question/15082545

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Using the molecular weight (258 g/mol) determine the amount of mmol of (3S)-2,2,- dibromo-3,4-dimethylpentane required.

Varvara68 [4.7K]

The question is incomplete, the complete question is;

With all of this data in hand, we can now set up our reaction. To begin we are going to use 0.7 g of (35)-2.2-dibromo-3,4-dimethylpentane. Question #7: Using the molecular weight (258 g/mol) determine the amount of mmol of (3S)-2,2,- dibromo-3,4-dimethylpentane required. Round to the tenths place

Answer:

2.70 mmols

Explanation:

Given that;

Mass of (3S)-2,2,- dibromo-3,4-dimethylpentane = 0.7 g

Molar mass of (3S)-2,2,- dibromo-3,4-dimethylpentane = 258 g/mol

From,

Number of moles = mass/molar mass

Number of moles of (3S)-2,2,- dibromo-3,4-dimethylpentane = 0.7g/258 g/mol = 2.7 ×10^-3 moles

Therefore;

Number of moles of (3S)-2,2,- dibromo-3,4-dimethylpentane = 2.70 mmols

8 0

4 years ago

In modern atomic theory, bohr's orbits are replaced by atomic orbitals. what is an atomic orbital?

Darya [45]

Bohr's theory states that the motion of the electron (particle) around the nucleus is very much similar to motion of the planets around the sun in the solar system. Both in the mathematical and physical sense.

The Bohr's Atomic theory only explains the motion of the electrons in discrete atomic orbitals that are predicted by the Bohr's equation.

It strictly implies that the electron only exists in these discreet orbitals and fails to explain anything about the nature of the electron in between the discrete orbitals.

The modern atomic theory does not share this limitation as it does not impose the electron to only occupy the discrete orbitals and neither does it impose particle nature upon the electron.

In the modern theory does not focus on describing the motion of the electron around the orbital but rather the probability of finding an electron around the nucleus. The modern atomic orbitals or electron clouds are the regions in which the probability of finding the electron is the highest when the wave function collapses. The Schrödinger's wave equation explains the evolution of the wave function in time. Hence enabling us to predict the future possible locations of the electron but never the exact location as that is impossible due to the Heisenberg's Uncertainty principle.

Learn more about Bohr's atomic orbitals by clicking here :

brainly.com/question/11872378

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4 0

2 years ago

A sample of an unknown biochemical compound is found to have a percent composition of 45.46 percent carbon, 7.63 percent hydroge

Leona [35]

Answer:

Formular = C₅H₁₁NO₃

Explanation:

The empirical formular is the simplest formular of a compound can have.

We use the steps below to obtain the empirical formular;

Step 1: Obtain the mass of each element present in grams. Element % = mass in g = m.

Carbon = 45.46% = 45.46g

Hydrogen = 7.63% = 7.63g

Nitrogen = 10% = 10g

Oxygen = 100% - (45.46% + 7.63% + 10%) = 36.31% = 36.31g

Step 2: Determine the number of moles of each type of atom present.

Molar amount (M) = m/atomic mass

Carbon = 45.46 / 12 = 3.7883

Hydrogen = 7.63 / 1 = 7.63

Nitrogen = 10 / 14 = 0.7143

Oxygen = 36.91 / 16 = 2.3069

Step 3: Divide the number of moles of each element by the smallest number of moles. Smallest = 0.7143

Carbon = 3.7883 / 0.7143 = 5.3035

Hydrogen = 7.63 / 0.7143 = 10.67

Nitrogen = 0.7143 / 0.7143 = 1

Oxygen = 2.2693 / 0.7143 = 3.1770

Step 4: Convert numbers to whole numbers

Carbon = 5

Hydrogen = 11

Nitrogen = 1

Oxygen = 3

Formular = C₅H₁₁NO₃

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4 years ago

The quantity 44 liters expressed in cubic meters is ____.

Sergeeva-Olga [200]

I think the answer is: D. 0.044 m3

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3 years ago

1. Consider the peptide with amino acid sequence NICE. Write the full name and the three-letter abbreviations of the amino acids

Alex Ar [27]

Answer:

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