What type(s) of bond(s) does carbon have a tendency to form?

How many grams of copper (II) hydroxide can be prepared from 2.4 grams of copper (II) nitrate (Cu(NO3)2 ) and excess sodium hydr

andreyandreev [35.5K]

Answer:

percentage yield = 67%

Explanation:

Mass of Cu(NO₃)₂ = 15.25 g

Mass of NaOH = 12.75 g

Percentage yield = ?

Solution:

Cu(NO₃)₂ + 2NaOH → Cu(OH)₂ + 2NaNO₃

Moles of Cu(NO₃)₂:

Number of moles = mass/ molar mass

Number of moles = 15.25 g /187.56 g/mol

Number of moles = 0.08 mol

Moles of NaOH :

Number of moles = mass/ molar mass

Number of moles = 12.75 g / 40 g/mol

Number of moles = 0.32 mol

Now we will compare the moles of Cu(OH)₂ with NaOH and Cu(NO₃)₂. NaOH : Cu(OH)₂

2 : 1

0.32 : 1/2×0.32 = 0.16 mol

Cu(NO₃)₂ : Cu(OH)₂

1 : 1

0.08 : 0.08

The number of moles produced by Cu(NO₃)₂ are less so it will limiting reactant.

Mass of Cu(OH)₂:

Mass = number of moles × molar mass

Mass = 0.08 mol × 97.6 g/mol

Mass = 7.808 g

Theoretical yield = 7.808 g

Percent yield:

percentage yield = Actual yield/ theoretical yield × 100

percentage yield = 5.23 g/ 7.808 g × 100

percentage yield = 0.67 × 100

percentage yield = 67%

5 0

2 years ago

1. What is the equality between mL and L?

Mice21 [21]

Answer:

1 liter (L) = 1000 milliliters (mL)

Explanation:

5 0

3 years ago

2CH2(g) + 50 (g) → 400/(g) + 2 H2O(g)

Nadusha1986 [10]

168.96 g of carbon dioxide (CO₂)

Explanation:

The chemical reaction representing the combustion of acetylene:

2 C₂H₂ (g) + 5 O₂ (g)→ 4 CO₂ (g) + 2 H₂O (g)

number of moles = mass / molecular weight

number of moles of acetylene (C₂H₂) = 50 / 26 = 1.92 moles

Taking in account the stoichiometry of the chemical reaction, we devise the following reasoning:

if 2 moles of acetylene (C₂H₂) produces 4 moles of carbon dioxide (CO₂)

then 1.92 moles of acetylene (C₂H₂) produces X moles of carbon dioxide (CO₂)

X = (1.92 × 4) / 2 = 3.84 moles of carbon dioxide (CO₂)

mass = number of moles × molecular weight

mass of carbon dioxide (CO₂) = 3.84 × 44 = 168.96 g

Learn more about:

combustion of hydrocarbons

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6 0

3 years ago

What is the name of the salt with the structure K2S

gavmur [86]

Potassium sulphide :)

6 0

3 years ago

Explain the difference in the boiling point of 2-methylpropane and 2-iodo-2-methylpropane in terms of both molecular polarity an

Len [333]

The Boiling Point of 2-methylpropane is approximately -11.7 °C, while, Boiling Point of <span>2-iodo-2-methylpropane is approximately 100 </span>°C.

As both compounds are Non-polar in nature, So there will be no dipole-dipole interactions between the molecules of said compounds.

The Interactions found in these compounds are London Dispersion Forces.

And among several factors at which London Dispersion Forces depends, one is the size of molecule.

Size of Molecule:
There is direct relation between size of molecule and London Dispersion forces. So, 2-iodo-2-methylpropane containing large atom (i.e. Iodine) experience greater interactions. So, due to greater interactions 2-iodo-2-methylpropane need more energy to separate from its partner molecules, Hence, high temperature is required to boil them.

6 0

3 years ago