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Anuta_ua [19.1K]
2 years ago
8

Help me with please !!!

Chemistry
1 answer:
egoroff_w [7]2 years ago
6 0

I would think the last one about the ozone layer
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Container which is heated
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3 years ago
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A reaction was suppose to produce 20 L of gas. Only 12 litters of gas were produced in the lab. What is the percent yield for th
pogonyaev

Answer:

\boxed {\boxed {\sf 60 \%}}

Explanation:

Percent yield is a ratio of the actual yield to the theoretical yield. It is found using this formula:

\% \ yield= \frac {actual \ yield}{theoretical \  yield} *100

The actual yield is 12 liters, because that was actually produced in the lab.

The theoretical yield is 20 liters, because that was the expected yield.

\% \ yield= \frac {12 \ L}{20\ L} *100

\% \ yield= 0.6*100

\% \ yield= 60

For this reaction, the percent yield is 60%.

5 0
2 years ago
g Given that 50.0 mL of 0.100 M magnesium bromide reacts with 13.9 mL of silver nitrate solution according to the unbalanced equ
ipn [44]

Answer:

0.719M AgNO₃

Explanation:

Based on the reaction:

MgBr₂ + 2AgNO₃ ⇄ 2AgBr + Mg(NO₃)₂

<em>1 mole of magnesium bromide reacts completely with 2 moles of AgNO₃</em>

<em />

To find molarity of AgNO₃ solution we need to determine moles of AgNO₃ and, as molarity is the ratio of moles over liter (13.9mL = 0.0139L). Now, to determine moles of AgNO₃ we need to use the reaction, thus:

<em>Moles AgNO₃:</em>

<em />

Moles of MgBr₂ are:

50.0mL = 0.050L * (0.100mol / L) = 0.00500 moles of MgBr₂.

As the silver nitrate reacts completely and 2 moles of AgNO₃ reacts per mole of MgBr₂:

0.00500 moles MgBr₂ * (2 moles AgNO₃ / 1 mole MgBr₂) =

0.0100 moles of AgNO₃ are in the solution.

And molarity is:

0.0100 moles AgNO₃ / 0.0139L =

<h3>0.719M AgNO₃</h3>
3 0
3 years ago
PLZ HELP, GIVING BRAINLIEST!!
Veseljchak [2.6K]

Answer:

2.29 moles of Cr₂O₃ are produced

Explanation:

This is the reaction:

4 Cr + 3O₂ → 2Cr₂O₃

Ratio for this equation is 4:2, so 4 moles of chromium can produce the half of moles of chromium(III) oxide

4.58 mol of Cr may produce (4.58  .2)/4 = 2.29 moles of Cr₂O₃

4 0
3 years ago
What’s the balance of this
lukranit [14]
It's the balance of chemical equation.
5 0
3 years ago
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