Benzoic acid reacts with sodium hydroxide based on the equation shown in the attached picture.
It is clear that the ration between the benzoic acid and the sodium hydroxide is 1:1 in this reaction.
So, to answer this question, we will calculate the number of moles of sodium hydroxide used, equate it to the number of moles of benzoic acid and then calculate the mass of the calculated number of moles.
molarity = number of moles of solute / liter of solvent
0.1 = number of moles of sodium hydroxide / 0.02 liters
number of moles of sodium hydroxide = 0.002 moles
Therefore, number of moles of benzoic acid is also 0.002 moles
molar mass of benzoic acid = <span>122.12 grams
Therefore, the required mass of benzoic acid = 0.002 x </span><span>122.12
= 0.2444 moles</span>
It is clear that the ration between the benzoic acid and the sodium hydroxide is 1:1 in this reaction.
So, to answer this question, we will calculate the number of moles of sodium hydroxide used, equate it to the number of moles of benzoic acid and then calculate the mass of the calculated number of moles.
molarity = number of moles of solute / liter of solvent
0.1 = number of moles of sodium hydroxide / 0.02 liters
number of moles of sodium hydroxide = 0.002 moles
Therefore, number of moles of benzoic acid is also 0.002 moles
molar mass of benzoic acid = <span>122.12 grams
Therefore, the required mass of benzoic acid = 0.002 x </span><span>122.12
= 0.2444 moles</span>