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andreev551 [17]
3 years ago
6

Which atom’s ionization energy is greater than that of phosphorus (P)?

Chemistry
1 answer:
Anna71 [15]3 years ago
7 0
The first ionisation energy of silicon is greater than that of phosphorus.
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C₄H₁₂ + 7O₂ --> 4CO₂ + 6H₂O

Explanation:

Organic molecules react with O2 to create water and CO2 in combustion processes. C4H12 is an organic molecule that combines with O2 to create water and CO2 as shown in the reactions.

As a result, this is the sole reaction that obeys the general combustion equation.

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What makes 3Ag2S+2Al->Al2S3+6Ag(s) oxidized and reduced
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It makes it thinner to calcite the rhythm
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C. If an electron is added to the outer shell, how will this affect the charge and volume of the atom?
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Answer:

An atom that gains or loses an electron becomes an ion. If it gains a negative electron, it becomes a negative ion. If it loses an electron it becomes a positive ion.

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Which reaction leads to the formation of a precipitate?
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2Ca(OH)2(aq) + 2FeCl3(aq) on the dead locs

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3. If x electrons are needed to displace 108 g silver from a solution which contains Ag ions,
ss7ja [257]

Answer:

Choice A. x electrons would be required for displacing 9\; \rm g of aluminum from a solution of \rm Al^{3+} ions.

Assumption: by "\rm Ag ions" the question meant \rm Ag^{+} with a charge of +1 on each ion.

Explanation:

The question states that the relative atomic mass of \rm Ag is 108. In other words, each mole of

Therefore, that 108\; \rm g\! of silver that were formed would contain 1\; \rm mol of silver atoms.

Metallic silver would precipitate out of this \rm Ag^{+} solution only after these ions are turned into \rm Ag atoms.

One \rm Ag^{+} ion carries one unit of positive electrical charge. On the other hand, each  e^{-} carries one unit of negative electrical charge.

Therefore, each \rm Ag^{+}\! ion will need to gain one electron to form a neutral \rm Ag atom.

{\rm Ag^{+}}\; (aq) + e^{-} \to {\rm Ag}\; (s).

At least  1\; \rm mol of electrons would be required to turn 1\; \rm mol\! of \rm Ag^{+} ions into that 1\; \rm mol\!\! of silver atoms (which have a mass of 108\; \rm g\!.)

Hence, x = 1\; \rm mol.

Unlike \rm Ag^{+} ions, each aluminum ion \rm Al^{3+} carries three units of positive electrical charge. That is three times the amount of charge on one \rm Ag^{+}\! ion. Therefore, three electrons will be required to turn one \rm Al^{3+}\! ion to an \rm Al atom.

{\rm Al^{3+}}\; (aq) + 3\, e^{-} \to {\rm Al}\; (s)

The question states that the relative atomic mass of \rm Al is 27. Therefore, each mole of \rm Al\! atoms would have a mass 27\; \rm g. There would be \displaystyle \frac{9\; \rm g}{27\; \rm g \cdot mol^{-1}} = \frac{1}{3} \; \rm mol of atoms in that 9\; \rm g of \rm Al\!\!.

It takes 3\; \rm mol of electrons to turn one mole of \rm Al^{3+} ions to one mole of \rm Al atoms. Hence, \displaystyle \frac{1}{3}\times 3\; \rm mol = 1\; \rm mol of electrons would be required to produce that \displaystyle \frac{1}{3}\; \rm mol of \rm Al\! atoms (which has a mass of 9\; \rm g) from \rm Al^{3+}\! ions.

That corresponds to the first choice, x electrons.

7 0
3 years ago
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