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denpristay [2]
3 years ago
8

Chlorine has an atomic number of 17.

Chemistry
2 answers:
zlopas [31]3 years ago
6 0

Answer:

A. 17

Explanation:

pishuonlain [190]3 years ago
4 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Atomic number is defined as the number of protons or number of electrons that are present in a neutral atom.  It is represented by the symbol 'Z'

Z = Atomic number = number of protons = number of electrons

We are given:

Atomic number of chlorine = 17

So, number of protons = 17

Hence, the correct answer is Option A.

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1.
german

Order of metals from least reactive to most reactive: B <C <A <D

<h3>Further explanation</h3>

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series  

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction  

Let's analyze the statement in the problem

I. Only A, C and D react with 1 mol/L HCl to give H₂(e)

M + HCl ⇒ MCl + H₂(MCl : alkali, MCl₂ : alkaline earth)

A, C and D can react with 1 mol / L HCl, meaning metals A, C and D are located to the left of element H (more reactive), and B in the right of element H

II. When A is added to solutions of the other metal ions, metallic B and C are  formed but not D.

This means that metal A is more reactive than metals B and C, while D is more reactive than A, so metal D is the most reactive

3 0
3 years ago
Baking soda and antacid tablets are examples of two common__________
attashe74 [19]

Bases

A base is a substance that dissociates into more hydroxide ions (-OH-) when dissolved in water. Bases are also good proton acceptors. Bases, therefore, reduce the number of H+ and increase OH- hence raising the pH of the solution.

B(aq) + H₂O(l) ⇌ BH⁺(aq) + OH⁻(aq)

Explanation:

Other properties of bases is that they are bitter to the taste and they feel slippery when touched. Strong bases are nonthlese very corrosive like acids. Bases turn red litmus paper blue. Most alkali hydroxides such as NaOH are bases.

Learn More:

For more on bases check out;

brainly.com/question/12574229

brainly.com/question/2015251

#LearnWithBrainly

7 0
3 years ago
How is genetic information is the same as a plum tree.
shutvik [7]

Answer:

This work was done in the European plum (Prunus domestica). The gene for PPV coat protein was separated from the PPV virus and inserted into the plum DNA, which was then regenerated and grown into complete plum trees. These trees now had the additional gene in their DNA and became resistant to PPV.

4 0
3 years ago
Under standard-state conditions, which of the following half-reactions occurs at the cathode during the electrolysis of aqueous
Slav-nsk [51]

Answer:

The following reaction will occur at cathode:

Ni^{+2}(aq)+2e--->Ni(s)

Explanation:

The two half reaction during electrolysis of aqueous nickel sulfate will be

a) anode reaction :

Water will undergo oxidation and will evolve oxygen gas at anode as shown in the given reaction:

2H_{2}O(l) ----> O_{2}(g) + 4H^{+}(aq) + 4e

b) Cathode reaction: The reduction of Nickel ion will occur by gain of two electrons as shown in the given equation:

Ni^{+2}(aq)+2e--->Ni(s)

Thus the overall reaction will be:

2H_{2}O(l) + 2Ni^{+2}----> O_{2}(g) + 4H^{+}(aq) + 2Ni(s)

6 0
3 years ago
Consider the following reaction at 298K.
lakkis [162]

The true statements are;

  • K < 0
  • Eocel  < 0

<h3>What is a redox reaction?</h3>

We define a redox reaction as one in which a specie is oxidized and another is reduced.

Now;

Eo cell = cell potential = -0.13 V - (+0.34 V) = -0.47 V

n =number of moles of electrons = 2 mole of electrons

K = equilibrium constant

ΔG = change in free energy

Eo cell = 0.0592/n log K

-0.47 =  0.0592/2 log K

log K =  -0.47  * 2/0.0592

K = 1.3 * 10^-16

ΔG = -nFEo cell

ΔG = -(2 * 96500 * -0.47)

ΔG = 90.7kJ

Learn more about Ecell:brainly.com/question/10203847

#SPJ1

8 0
2 years ago
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