A=bh/2, h=b-5 so
A=(b/2)(b-5)
A=(b^2-5b)/2 and A=42 so:
(b^2-5b)/2=42
b^2-5b=84
b^2-5b-84=0
b^2-12b+7b-84=0
b(b-12)+7(b-12)=0
(b+7)(b-12)=0 and since b>0
b=12m
Answer:
70/100 (58)
0.70 (58)
Step-by-step explanation:
If LllM then the consecutive angles shoud be supplementary(=180)
x-5+2x+5=180
x+2x=180
3x=180
x=60
Answer:x=60
Answer: 4
Step-by-step explanation:
The procedure is pretty basic. First you have to substitute what you know in the equation. So as you know f(x)=18, just substitute f(x) by 18, leaving it like 18 = 3x + 6.
Then you have to start to move things around. First start with the + 6 that is adding, so it moves to the other side as a substraction giving 18 - 6 = 3x -> 12 = 3x. The next step is to get rid of that 3, so because it's multiplying the x, it moves to the other side as a division leaving you with 12 ÷ 3 = x -> 4 = x. There you have the answer! For a value/y of 18 in that function, the x is 4
Answer and work down below. Let me know if you have any questions