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Norma-Jean [14]
3 years ago
8

A conference room is in the shape of a rectangle. Its floor has a length of (x − 4) meters and a width of (3x − 1) meters. The e

xpression below represents the area of the floor of the room in square meters:
(x − 4)(3x − 1)

Which of the following simplified expressions represents the area of the floor of the conference room in square meters?

x2 − 13x + 4
3x2 − 13x + 4
3x2 − 11x + 4
x2 − 12x + 4
Mathematics
2 answers:
Naddik [55]3 years ago
7 0

Answer:

3x^2−13x+4

Step-by-step explanation:

(x−4)(3x−1)

=(x+−4)(3x+−1)

=(x)(3x)+(x)(−1)+(−4)(3x)+(−4)(−1)

=3x^2−x−12x+4

=3x^2−13x+4

weqwewe [10]3 years ago
4 0

Answer:

Option A. 3x² - 13x + 4 is the answer.

Step-by-step explanation:

A conference room is in the shape of a rectangle. Its floor has a length of (x - 4) and width of (3x - 1) meters.

The expression that represents the area of the room is (x - 4)(3x -1) meter²

We further simplify this expression representing the area of the conference room.

(x - 4)(3x -1) = x(3x -1) - 4(3x -1) [Distributive law]

= 3x² - x - 12x + 4

= 3x² - 13x + 4

Option A. 3x² - 13x + 4 is the simplified form of the given expression.

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Answer:

Step-by-step explanation:

(a)

Consider the following:

A=\frac{\pi}{4}=45°\\\\B=\frac{\pi}{3}=60°

Use sine rule,

\frac{b}{a}=\frac{\sinB}{\sin A}
\\\\=\frac{\sin{\frac{\pi}{3}}
}{\sin{\frac{\pi}{4}}}\\\\=\frac{[\frac{\sqrt{3}}{2}]}{\frac{1}{\sqrt{2}}}\\\\=\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{1}=\sqrt{\frac{3}{2}}

Again consider,

\frac{b}{a}=\frac{\sin{B}}{\sin{A}}
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Thus, the angle B is function of A is, B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Now find \frac{dB}{dA}

Differentiate implicitly the function \sin{B}=\sqrt{\frac{3}{2}}\sin{A} with respect to A to get,

\cos {B}.\frac{dB}{dA}=\sqrt{\frac{3}{2}}\cos A\\\\\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos A}{\cos B}

b)

When A=\frac{\pi}{4},B=\frac{\pi}{3}, the value of \frac{dB}{dA} is,

\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos {\frac{\pi}{4}}}{\cos {\frac{\pi}{3}}}\\\\=\sqrt{\frac{3}{2}}.\frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}}\\\\=\sqrt{3}

c)

In general, the linear approximation at x= a is,

f(x)=f'(x).(x-a)+f(a)

Here the function f(A)=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

At A=\frac{\pi}{4}

f(\frac{\pi}{4})=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{\frac{\pi}{4}}]\\\\=\sin^{-1}[\sqrt{\frac{3}{2}}.\frac{1}{\sqrt{2}}]\\\\\=\sin^{-1}(\frac{\sqrt{2}}{2})\\\\=\frac{\pi}{3}

And,

f'(A)=\frac{dB}{dA}=\sqrt{3} from part b

Therefore, the linear approximation at A=\frac{\pi}{4} is,

f(x)=f'(A).(x-A)+f(A)\\\\=f'(\frac{\pi}{4}).(x-\frac{\pi}{4})+f(\frac{\pi}{4})\\\\=\sqrt{3}.[x-\frac{\pi}{4}]+\frac{\pi}{3}

d)

Use part (c), when A=46°, B is approximately,

B=f(46°)=\sqrt{3}[46°-\frac{\pi}{4}]+\frac{\pi}{3}\\\\=\sqrt{3}(1°)+\frac{\pi}{3}\\\\=61.732°

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Find the slope:

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3/4

y = mx + b

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Substitute any of the point's coordinate in the equation.

I'll pick (0,-1)

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y-intercept Equation:

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The least common multiple must have factors that include all of these*, so must be ...

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* you can describe the LCM as the product of the unique factors to their highest powers. 20 has 2 raised to the 2nd power. 25 has 5 raised to the 2nd power, which is a higher power of 5 than is present in the factorization of 20. Hence the LCM must have 2² and 5² as factors.

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