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just olya [345]
3 years ago
13

What is the factored form of x3 + 64?

Mathematics
1 answer:
AVprozaik [17]3 years ago
8 0

Option B, (x+4)(x^2-4x+16)

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Please help out thanks :) ​
Mkey [24]
The correct answer is D The last one


Step by step is below

Hopefully this help you


Have a great day :)

3 0
3 years ago
1. Which would be a more helpful for solving the system: adding the two equations or subtracting
ira [324]

Answer:

1) Subtracting one from the other

2) x = 0.375 and y = 0.125

Step-by-step explanation:

Equation 1 :

\frac{2x+1}{2y}=7\\\\

Equation 2:

\frac{6x-1}{2y}=5

To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,

\frac{2x+1}{2y} =7\\\\2x+1=14y\\\\Multiplying\ Equation\ 1\  with\ 6\\\\12x+6=84y

Now for the second equation:

\frac{6x-1}{2y}=5\\\\6x-1=10y\\\\Multiplying\ equation\ 2\ with\ 2 \\\\12x-2=20y

Now subtracting equation 2 from equation 1

12x+6=84y\\\\12x-2=20y\\\\Subtracting\ leads\ to\\12x-12x+6-(-2)=84y-20y\\0+8=64y\\8=64y\\8/64=y\\0.125=y

now insert this value of y into any equation

lets insert it into equation 1

\frac{2x+1}{2y} =7\\\\2x+1=14y\\2x+1=14(0.125)\\2x+1=1.75\\2x=1.75-1\\2x=0.75\\x=0.75/2\\x-0.375

5 0
3 years ago
A spinner has 10 equal sections numbered 1 through 10. What is the probability of
Nezavi [6.7K]

Answer:

The correct answer is C. 1/10.

Step-by-step explanation:

Given that a spinner has 10 equal sections numbered 1 through 10, to determine what is the probability of landing on the 6, the following calculation must be performed:

6 = 1 side only

10 = 10 options

1/10 = X

Therefore, the probability of the spinner landing on the 6 is 1/10.

3 0
3 years ago
If 18 percent VAT is included in the price
natta225 [31]

Answer:

the formula is VAT %op cp ×13500 do that using this formul6 is should correct

4 0
2 years ago
Pls help me i give 15 points help me with the three questions please
VLD [36.1K]

Answer:

I dont know sorry!! I would help though

Step-by-step explanation:

6 0
2 years ago
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