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3 years ago

The least common denominator is the least common multiple of the ————of the fractions.

Mathematics

1 answer:

Lapatulllka [165]3 years ago

6 0

Answer:

<u>denominators</u>

Step-by-step explanation:

This is vocabulary term definition (for "least common denominator"). This missing word is "denominators."

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The perimeter of the figure to the right, made up of identical squares, is equal to 56 cm. What is the area of the figure?

Mamont248 [21]

The area of the square will be 196cm².

<h3>How to calculate the area?</h3>

It should be noted that the perimeter of a square is the addition of all its sides. Therefore, the length of the side will be:

= 56/4

= 14

Therefore, the area of the figure will be:

= 14²

= 14 × 14

= 196cm²

Learn more about area on:

brainly.com/question/25292087

#SPJ1

4 0

2 years ago

Suppose X has a continuous uniform distribution over the interval [1.3, 6.2]. Round your answers to 3 decimal places.

goldenfox [79]

Answer:

(a) 3.75

(b) 2.00083

Step-by-step explanation:

It is provided that X has a continuous uniform distribution over the interval [1.3, 6.2].

(a)

Compute the mean of X as follows:

$\mu_{X}=\frac{a+b}{2}=\frac{1.3+6.2}{2}=3.75$

(b)

Compute the variance of X as follows:

$\sigm^{2}_{X}=\frac{(b-a)^{2}}{12}=\frac{(6.2-1.3)^{2}}{12}=2.00083$

(c)

Compute the value of P(X < 3.7) as follows:

$P(X < 3.7)=\int\limits^{3.7}_{1.3}{\frac{1}{6.2-1.3}}\, dx\\\\=\frac{1}{4.9}\times [x]^{3.7}_{1.3}\\\\=\frac{3.7-1.3}{4.9}\\\\\approx 0.4898$

Thus, the value of P(X < 3.7) is 0.4898.

5 0

2 years ago

Please help with this math

Luden [163]

The first one
$2 \times 3 \times 5$
second one
$2 \times5 + 3$

third one
$2 \times 3 - 5$
last one
$2 \times 3 + 5$

3 0

3 years ago

A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the

Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision Variable Constraint Constraint

A 65 65 100

B 80 80 80

C 90 90 90

14100 300 300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

A B C Unit price

Need of X 2 1 1 $20

Need of Y 2 3 2 $30

Need of Z 2 2 3 $25

Price of

manufac - $200 $240 $220

turing

Now, for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

${(100 - A) + (80 - B) +(90 - C) } + \$40$

This should be subtracted from profit.

So, we have to maximize the profit

$Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};$

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

$2A + B +C \le 300$ due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

$A \le 100$

$B \le 80$

$C \le 90$

and $A, B, C \ge 0$ because they are positive quantities

The objective is:

$\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}$

A, B, C $\to$ Decision Varaibles;

Constraint are:

$A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0$

6 0

3 years ago

Investors buy a studio apartment for $180,000. Of this amount, they have a down payment of $36,000. Their down payment is what

Tema [17]

Answer:

27,000 is the answer

Step-by-step explanation:

4 0

3 years ago