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meriva
3 years ago
12

Billy runs at a pace of 2.25 ft/sec. how many feet can billy travel in 10 seconds?

Mathematics
1 answer:
Lilit [14]3 years ago
4 0
10*2.25= 22.5 ft, that’s it
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Solve the inequality 11 < x - 16
asambeis [7]

Answer:

The choice B.

x > 27

Step-by-step explanation:

11 < x - 16 \\ 11 + 16 < x - 16 + 16 \\ 27 < x \\ x > 27

I hope I helped you^_^

8 0
2 years ago
The price of a cup of coffee was $2.65 yesterday. Today, the price fell to $2.30 . Find the percentage decrease. Round your answ
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Percent change = change/original * 100
(2.65 - 2.30)/ 2.65    * 100
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13.2 % decrease
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7 0
3 years ago
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julia-pushkina [17]

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Step-by-step explanation:

8 0
3 years ago
Prove that the diagonals of a parallelogram bisect each other​
Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof :\begin{array}{ |c| c |  c |  } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In  \: \triangle ^{s}  \:AOB \: and \: COD  } \\  \sf{(i)}&  \sf{ \angle \: OAB =  \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\  \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\  \sf{(iii)} &\sf{ \angle \: OBA=  \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\  \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}.          Proved ✔

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

☄ Hope I helped! ♡

☃ Let me know if you have any questions! ♪

\underbrace{ \overbrace  {\mathfrak{Carry \: On \: Learning}}} ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

5 0
3 years ago
F is the midpoint of Gh. Point g is located at 32 abd f is located at 105. What is the locateion of h
Nuetrik [128]
Do the midpoint formula

3 0
3 years ago
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