sold inventory for $ 320 comma 000, terms 3/10, n/30. Cost of goods sold was $ 168 comma 000. How much sales revenue will Hai
1 answer:
You might be interested in
Answer:
Total Maximized Profit = $2612.5
Explanation:
given data
Total Cost TC = 10(QE + QW)
QE = 100 - 2PE
QW = 100 - PW
solution
we consider here Q is = QE + QW
so total cost TC = 10 Q
we first derive it Marginal Cost by taking derivative of TC w.r.t Q that is
MC =
MC = 10
so when crusty practice price discrimination then it will different marginal revenue from each market is
QE = 100 - 2PE
and
Total Revenue from market E is
E = TRE = QE × PE
E = 100PE - 2PE²
and
Marginal Revenue from E is
E = MRE =
E = 100 - 4PE
and
now we put MRE = MC
100 - 4PE = 10
PE = $22.5
and here QE will be
QE = 100 - 2PE
QE = 100 - 45
QE = 55 units
and
TRE = 55 × 22.5
TRE = $1237.5
and
now Considering second neighborhood W
QW = 100 - PW
so here
TRW = 100PW - PW²
and
MRW = 100 - 2PW
now we equating MRW with MC
so it will be
100 - 2PW = 10
PW = $45
and
Q = 100 - PW
Q = 100-45
Q = 55 units
so
TRW = 55 × 45
TRW = $2475
so here
Total Revenue will be
Total Revenue = TRE + TRW
Total Revenue = $1237.5 + $2475
Total Revenue = $3712.5
and
Total Cost will be
Total Cost = 10(55+55)
Total Cost = $1100
and
Total Maximized Profit will be
Total Maximized Profit = TR -TC
Total Maximized Profit = $3712.5 - $1100
Total Maximized Profit = $2612.5