Step-by-step explanation:
Given
(x1 , y1) = ( 0 , 3)
(x2 , y2) = ( 1 , 8)
Now
Gradient =


Hope it will help :)

<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
Let the speed be x
Distance = Time x Speed = 9x
<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)
Since both the distance they traveled are the same, we equate the distance to solve for x.
<u>Solve for x:</u>
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60
<u>Find the speed:</u>
x = 60 mph
x + 48= 108 mph
Answer: The spend of the two trains are 60 mph and 108 mph.
Given the equation:

(a) You can identify that the student applied the Subtraction Property of Equality by subtraction 3 from both sides of the equation:

However, the student made a mistake when adding the numbers on the right side.
Since you have two numbers with the same sign on the right side of the equation, you must add them, not subtract them and use the same sign in the result. Then, the steps to add them are:
- Add their Absolute values (their values without the negative sign).
- Write the sum with the negative sign.
Then:

(b) The correct procedure is:
1. Apply the Subtraction Property of Equality by subtracting 3 from both sides (as you did in the previous part):

2. Apply the Multiplication Property of Equality by multiplying both sides of the equation by 6:

Hence, the answers are:
(a) The student made a mistake by adding the numbers -18 and -3:

(b) The value of "x" should be:
Answer:
C:
or 
Step-by-step explanation:
To solve the equation
we need to factor it
We are looking for two numbers that when multiplied give -12 and when added give -x
This means that when factored, the equation would be 
Now we can set each of these equal to 0, which means that at
and
, the equation will equal 0