6:3 = 6/3 = 2
13 to 4 = 13:4 = 13/4 = 3.25
19/2 = 9.5
15 to 10 = 15:10 = 15/10 = 1.5
8:2 = 8/2 = 4
From the least to the greatest:
15 to 10 , 6:3, 13 to 4, 19/2
I hope this explains it.
Answer:
The sample space for selecting the group to test contains <u>2,300</u> elementary events.
Step-by-step explanation:
There are a total of <em>N</em> = 25 aluminum castings.
Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).
It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.
In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.
The formula to compute the combinations of k items from n is given by the formula:

Compute the number of samples that are possible as follows:


The sample space for selecting the group to test contains <u>2,300</u> elementary events.
I know the B is 2
Sorry I don't know the A