Answer:
He drove the rest of the trip at 30 miles per hour
Step-by-step explanation:
The rule of the distance is D = v × t, where
∵ It is 170 miles from Bruce's house to the city where his brother lives
∴ D = 170 miles
∵ He drove for 2 hours at 55 miles per hour
∴ t1 = 2 hours and v1 = 55 miles/hour
→ By using the rule above find the distance of this part of his trip
∴ D1 = 55 × 2 = 110 miles
∵ The rest of the trip took 2 hours
∴ t2 = 2 hours
∵ D = D1 + D2
→ Substitute the values of D and D1 to find D2
∴ 170 = 110 + D2
→ Subtract 110 from both sides to find D2
∴ 60 = D2
∴ D2 = 170 - 110 = 60 miles
∵ The rest of the trip is 60 miles
∵ It took 2 hours
∵ D2 = v2 × t2
∴ 60 = v2 × 2
→ Divide both sides by 2
∴ 30 = v2
∴ v2 = 30 miles/hour
∴ He drove the rest of the trip at 30 miles per hour
Given:
Hyperbola
a=55,000 km and c=81,000 km
hyperbola is the origin and the
transverse axis is horizontal
Required:
Equation of the path of a
satellite
Solution:
Formula for hyperbola, (x-h)2/a2
– (x-k)2/b2 = 1
At origin, (h, k) = (0, 0)
(x-0)2/(55000)2 – (x-0)2/(81000)2
= 1
<span>X2/12100 – y2/26244 = 250000</span>
Answer:
For the first 30 minutes, we will have a line with a given steepness, this will represent the 30 minutes riding at a fast pace.
Then he stops for 20 minutes, we will represent this with a constant line.
Then he again moves for another 30 minutes, but with a slower pace than in the first 30 minutes, then this line will be less steep than the first line.
A sketch of this situation can be seen below.
Answer:
10
Step-by-step explanation:
find out f(2)
f(2)= (3×2×2) - 4= 8
then g(8) = 16 - 6= 10
