Question

Jason takes off across level water on his jet-powered skis

Answer 1

Thrust - Friction = mass * acceleration

Friction = coefficient * mass * gravity
Friction = 0.10 * 75 * 9.8 = 73.5 N

Substituting:
200N - 73.5 = 75a
a = 1.69 m/s^2

Obtaining final velocity at the end of 41 seconds:
Vf = at
Vf = 1.69 (41)
Vf = 69.15 m/s

Using the formula for displacement for linear motion problems:

s = Vo*t + (1/2)a*t^2
s = 0 + (1/2)(1.69)(41^2)
s = 1420.445 meters

After he runs out of fuel, we use the following formula to find the distance that he coasts:

F = ma = coefficient*m*g
a = 0.10(9.8)
a = -0.98

Vf^2 = Vo^2 + 2as
0 = 69.15^2 + 2(-0.98)s
s = 2439. 65

Adding the 2 displacements together to obtain the total distance:

Total distance = 2439.65 + 1420.45 meters
Total distance = 3860.1 meters