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4 years ago

Jason takes off across level water on his jet-powered skis

1 answer:

4 0

Thrust - Friction = mass * acceleration

Friction = coefficient * mass * gravity
Friction = 0.10 * 75 * 9.8 = 73.5 N

Substituting:
200N - 73.5 = 75a
a = 1.69 m/s^2

Obtaining final velocity at the end of 41 seconds:
Vf = at
Vf = 1.69 (41)
Vf = 69.15 m/s

Using the formula for displacement for linear motion problems:

s = Vo*t + (1/2)a*t^2
s = 0 + (1/2)(1.69)(41^2)
s = 1420.445 meters

After he runs out of fuel, we use the following formula to find the distance that he coasts:

F = ma = coefficient*m*g
a = 0.10(9.8)
a = -0.98

Vf^2 = Vo^2 + 2as
0 = 69.15^2 + 2(-0.98)s
s = 2439. 65

Adding the 2 displacements together to obtain the total distance:

Total distance = 2439.65 + <span>1420.45 meters
Total distance = 3860.1 meters</span>

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50. A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage to 335 kV. The secondar

Sedaia [141]

Answer:

Explanation:

a ) The transformer steps up the voltage from 12000 V to 335000 V . Voltage in primary is 12000 V and in the secondary it is 335000 V in old transformer

If n₁ be no of turns in primary coil and n₂ be no of turns in secondary coils

the formula is

n₂ / n₁ = voltage in secondry / voltage in primary

n₂ / n₁ = 335000 / 12000

ratio of turns in old transformer

= 27.9

ratio of turns in new transformer

n₃ / n₁ = 750 / 12 ( n₃ is no of turns in the secondary of new transformer )

= 62.5

T he ratio of turns in the new secondary compared with the old secondary

n₃ / n₂ = 62.5 / 27.9

= 2.24

b ) Current in secondary / current in primary

= turns in primary / turns in secondary

current output ratio of old

= Current in secondary / current in primary

= n₁ / n₂

= 12 / 335

= .03582

current output ratio of new

= Current in secondary / current in primary

= n₁ / n₃

= 12 / 750

= .016

The ratio of new current output to old output (at 335 kV) for the same power

= .016 / .03582

= .4466

c ) power loss in new

= (current in secondary )² x resistance of secondary

=( .016 x current in primary )² x R

= 2.56 X 10⁻⁴ X ( current in primary )² x R

power loss in old

= (current in secondary )² x resistance of secondary

=( .03582 x current in primary )² x R

= 12.83 X 10⁻⁴ X ( current in primary )² x R

ratio of new line power loss to old

= 2.56 / 12.83

= .199

7 0

3 years ago

A radio signal takes 1.28 s to travel from a transmitter on the Moon to the surface of Earth. The radio waves travel at 3.00108

yulyashka [42]

Answer:

s = 3.84 x 10⁸ m

Explanation:

The distance traveled by an object, while in uniform motion, is given by the following equation:

s = vt

where,

s = distance covered

v = speed

t = time interval

In this case:

s = distance between Moon and Earth = ?

v = speed of radio waves = 3 x 10⁸ m/s

t = time taken to travel = 1.28 s

Therefore,

s = (3 x 10⁸ m/s)(1.28 s)

3 0

4 years ago

Mercury is in the 80th position in the periodic table. How many protons does it have?

Verdich [7]

Mercury has 80 protons. Ironic?

7 0

3 years ago

Read 2 more answers

Momentum is usually not exactly conserved in a real world demonstration of momentum conservation. What is a possible reason for

Maksim231197 [3]

Answer:

For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.

Explanation:

Hope this helps

5 0

3 years ago

A merry go round exerts a force of 1000 N on a rider on the

SVEN [57.7K]

Answer:

The radius of the circle made by the person on the merry go round is 74.55 meters

Explanation:

The given parameters are;

The force the merry go round exerts on the rider = 1000 N

The time it takes the merry go round to make one complete revolution = 15 seconds

The weight of the person = 750 N

The radius of the circle made by the person on the merry go round = r

We have;

$F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r$

Where;

m = The mass of the person

v = The velocity of the person

$F_c$ = The centrifugal force acting on the person = 1,000 N

r = The radius of the circle made by the person on the merry go round

ω = Angular velocity = 2·π/15 rad/s

We have;

The mass of the person = The weight/(The acceleration due to gravity, g)

∴ The mass of the person = 750/9.81 ≈ 76.45 kg

By substituting the calculated and known values into the equation for the centripetal force, we have;

$F_c$ = m × ω² × r

1000 = 76.45 × (2·π/15)² × r

r = 1000/(76.45 × (2·π/15)²) = 74.55 m

The radius of the circle made by the person on the merry go round = r = 74.55 m.

3 0

3 years ago