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2 years ago

Two protons (each with q = 1.60 x 10-19)

Physics

1 answer:

otez555 [7]2 years ago

5 0

Answer:

230.4 N

Explanation:

From the question given above, the following data were obtained:

Charge (q) of each protons = 1.6×10¯¹⁹ C

Distance apart (r) = 1×10¯¹⁵ m

Force (F) =?

NOTE: Electric constant (K) = 9×10⁹ Nm²/C²

The force exerted can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × (1.6×10¯¹⁹)² / (1×10¯¹⁵)²

F = 9×10⁹ × 2.56×10¯³⁸ / 1×10¯³⁰

F = 2.304×10¯²⁸ / 1×10¯³⁰

F = 230.4 N

Therefore, the force exerted is 230.4 N

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The outer planets are similar to the planet Earth; they just happen to be farther away from the Sun.

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Answer:

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Explanation:

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3 years ago

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The brakes on your automobile are capable of creating a deceleration of 4.6 m/s^2. If you are going 114 km/h and suddenly see a

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Answer:

The minimum time to get the car under max. speed limit of 79 km/h is 2.11 seconds.

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$a=\frac{V_f-V_0}{t}$

isolating "t" from this equation:

$t=\frac{V_f-V_0}{a}$

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$V_f= 79 km/h$

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First we must convert velocity from km/h to m/s to be consistent with units.

$79\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{79*1000}{3600}=21.94 m/s$

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3 years ago

Having landed on a newly discovered planet, an astronaut sets up a simple pendulum of length 1.25 m and finds that it makes 419

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Answer:

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Explanation:

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$f=\frac{419}{60} \\f=6.98Hz$

The angular frequency is:

ω $=2\pi f$

ω $=2*\frac{22}{7} *6.98$

ω $=43.88rad /sec$

Now we can apply simple pendulum relationship

ω $=\sqrt{\frac{g}{l} }$

make g the subject of the formula

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3 years ago

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oksano4ka [1.4K]

Answer:

About 2 units.

Explanation:

We assume that there is no heat dissipating instrument in the room

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where

$Q_{light}$ = 10*100 W =1 KW

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$Q_{cooling}$ = 1+4+4.17=9.17 KW

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which is approximately 2 units

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