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Eddi Din [679]
3 years ago
6

Which of the following scientists taught physics in the United States?

Physics
2 answers:
Sergio039 [100]3 years ago
6 0
<span>Subrahmanyan Chandrasekhar

</span>
GREYUIT [131]3 years ago
6 0

Answer : Option C) Subrahmanyan Chandrasekhar

Explanation : Scientist Subrahmanyan Chandrasekhar was a long-time professor in the University of Chicago. He has been awarded noble prize for Physics during his life time. He was an Indian by origin but later settled in US for his professional life.

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An airplane travels 3,260 kilometers in 4 hours. What is the airplane’s average speed?
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3260÷4=815 which is you average seed
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3 years ago
Gawaingnpang nkabuhayan,hamon at oportinidad​
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gawaingnpang nkabuhayan, hamon at oportinidad

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3 years ago
An early method of measuring the speed of light makes use of a rotating slotted wheel. A beam of light passes through one of the
Readme [11.4K]

Answer:

4.7 x 10³ rad / s

Explanation:

During the time light goes and comes back , one slot is replaced by next slot while rotating  before the light source

Time taken by light to travel a distance of 2 x 500 m is

= (2 x 500) / 3 x 10⁸

= 3.333 x 10⁻⁶ s .

In this time period, two consecutive slots come before the source of light one after another by rotation. There are 400 slots so time taken to make one rotation

= 3.333 x 10⁻⁶ x 400

= 13.33 x 10⁻⁴ s

This is the time period so

T = 13.33 X 10⁻⁴

Angular speed

= 2π / T

= \frac{2\times3.14}{13.33\times10^{-4}}

4.7 x 10³ rad / s

5 0
2 years ago
a ball is tossed straight up in the air to a maximum height of 25 meters before returning to the point that it was thrown, where
boyakko [2]

Answer:

height=25

velocity=8

force of gravity=10

Answer =2000

5 0
2 years ago
A 150kg motorcycle starts from rest and accelerates at a constant rate along with a distance of 350m. The applied force is 250N
mart [117]

Answer:

205N

Explanation:

The net force (F) is the difference between the applied force(F_{A}) and the kinetic frictional force(F_{R}). i.e

F = F_{A} - F_{R}    -----------------(i)

Note that;

F_{R} = μmg

Where;

μ = coefficient of kinetic friction

m = mass of the body

g = acceleration due to gravity = 10m/s²

Equation (i) then becomes;

F = F_{A} - μmg        -------------------(ii)

<em>Given from question;</em>

m = mass of motorcycle = 150kg

μ = 0.03

F_{A} = 250N

Substitute these values into equation (ii) as follows;

F = 250 - (0.03 x 150 x 10)

F = 250 - (45)

F = 205N

Therefore, the net force applied to the motorcycle is 205N

3 0
3 years ago
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