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Nezavi [6.7K]
4 years ago
14

Calculate the energy E (in MeV) released in the following nuclear fission reaction: 242 Am + X → 90 Sr + 149 La + 4 n Start by c

ompleting the reaction, and use the following nuclear masses: 242 Am = 242.0595490 u, 90 Sr = 89.9077387 u, and 149 La = 148.934733 u. The symbol X represents an unknown particle.
Chemistry
1 answer:
KonstantinChe [14]4 years ago
8 0

Answer:

177.993 MeV

Explanation:

Nuclear fission refers to a process where a nucleus is broken into smaller ones.

m(Am) = 242.0595490 u, m(Sr) = 89.9077387 u, m(La) = 148.934733 u and m(n) = 1.008665 u. To find the mass of X, we sum up the masses on both side and subtract them according to the equation given

242 + X = 90 +149 + 4

X = 243 - 242 = 1

so X is a neutron

next we calculate the Δm ( change in mass)

Δm = mass reactant - mass of product

(242.0595490 + 1.008665 ) - ( 89.9077387 + 148.934733  + 4 (1.008665))

= 243.068214 - 242.8771317 = 0.1910823 u

using the formula

E = (Δm) c² = 0.1910823 u × c² × \frac{931.5MeV}{c^2}× \frac{1}{u} = 177.993 MeV

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Answer:

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Explanation:

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8 0
3 years ago
How many grams of LiOH are needed to make 25 mL of a 0.125 M solution?
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Answer:

0.0734 grams LiOH

Explanation:

The molarity formula looks like this:

Molarity (M) = moles / volume (L)

You are given the molarity and volume (in mL). Therefore, you can plug these values into the equation and solve for moles (after you convert from mL to L).

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0.003125 moles           23.499 g
------------------------   x   -------------------  =  0.0734 grams LiOH
                                        1 mole

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     Good luck!

6 0
3 years ago
Read 2 more answers
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