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Anastaziya [24]
2 years ago
6

Consider these two entries from a fictional table of standard reduction potentials.

Chemistry
1 answer:
Vika [28.1K]2 years ago
8 0

Answer:

1.89 V

Explanation:

To calculate the standard cell potential, subtract the reduction potential of the anode from the reduction potential of the cathode.

So for your calculation,

-0.22 V - (-2.11 V)= 1.89 V

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How many grams of KCl is needed to make .75 L of a 1 M solution of KCl?
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Answer:

The answer to your question is 25.9 g of KCl

Explanation:

Data

Grams of KCl = ?

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Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

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Substitution

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Simplification

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Use proportions to find the grams of KCl

                          34.5 g of KCl ----------------  1 mol

                             x                  ----------------  0.75 moles

                            x = (0.75 x 34.5) / 1

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