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Anastaziya [24]
3 years ago
6

Consider these two entries from a fictional table of standard reduction potentials.

Chemistry
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

1.89 V

Explanation:

To calculate the standard cell potential, subtract the reduction potential of the anode from the reduction potential of the cathode.

So for your calculation,

-0.22 V - (-2.11 V)= 1.89 V

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What is the buoyant force of a dog that displaces 10 pounds of water?
Troyanec [42]

Answer:

pls answer this link for the answer :D

Explanation:

brainly.com/question/22200936

5 0
3 years ago
A particular forest is 10,000 acres. Determine its size in hectares. (1 hectare = 2.47
igor_vitrenko [27]

Taking into account the change of units, a particular forest is 4,048.58 hectares.

<h3>Definition of rule of three</h3>

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, the direct rule of three must be applied using the following formula, where a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: x= (c×b)÷ a

The direct rule of three is the rule applied in this case where there is a change of units.

<h3>Size in hectareas</h3>

To perform in this case the conversion of units, you must first know that 1 hectare = 2.47 acres.

So, the rule of three can be used as follow: if 2.47 acres is 1 hectare, 10,000 acres equals how many hectares?

2.47 acres ⇒ 1 hectare

10,000 acres ⇒ x

So: x= (10,000 acres ×1 hectare)÷ 2.47 acres

Solving:

<u><em>x= 4,048.58 hetares</em></u>

In summary, a particular forest is 4,048.58 hectares.

Learn more with this example:

brainly.com/question/12482948

#SPJ1

8 0
2 years ago
Which statement must be true for any chemical reaction at equilibrium?
sergejj [24]
<span>The correct answer is 3. The concentration of the product and the concentration of the reactants are equal. That is because matter cannot be created or destroyed and the product cannot randomly become something else in the reaction, nor can a reactant change into something different. Simply put, you cannot turn things like water into gold because there will always be an equilibrium.</span>
4 0
4 years ago
Read 2 more answers
Fructose‑2,6‑bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolys
olga_2 [115]

Answer:

Activate glycolysis/Inhibit gluconeogenesis: Increased levels of fructose-2,6-bisphosphate, activation of PFK-2

Activate gluconeogenesis/Inhibit glycolysis: Increased levels of glucagon, Increased levels of cAMP, Activation of fructose-2,6-bisphosphatase (FBPase-2)

<em>Note: The question is incomplete. The complete question is given below and in the attachment.</em>

<em>Fructose‑2,6‑bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolysis and the fructose‑1,6‑bisphosphatase reaction of gluconeogenesis. In turn, the concentration of fructose‑2,6‑bisphosphate is regulated by many hormones, second messengers, and enzymes. How do the following affect glycolysis and gluconeogenesis? </em>

Explanation:

Fructose-2,6-bisphosphate is an allosteric effector for the enzymes phosphofructokinase-1 (PFK-1) and fructose-1,6-bisphosphatase (FBPase-1). It increases the affinity of PFK-1 for fructose-6-phosphate thereby activating glycolysis. However, it reduces the affinity of FBPase-1 for its substrate, fructose-1,6-bisphosphate thereby inhibiting gluconeogenesis.

Activation of phosphofructokinase-2 activates glycolysis and inhibits gluconeogenesis by catalyzing the phosphorylation of fructose-6-phosphate to form fructose-2,6-bisphosphate.

Increased levels of glucagon stimulates the synthesis of cAMpP which activates cAMP-dependent ptrotein kinase which phosphorylates the bifunctional enzyme PFK-2/FBPase-2. The phosphorylation of this enzyme inhibits its PFK-2 activity and activates its FBPase-2 activity. This results in the activation of gluconeogenesis and inhibition of glycolysis.

Fructose-2,6-bisphosphatase breaks down fructose-2,6-bisphosphate to fructose-6-phospshate and a phosphoryl group. This results in the activation of gluconeogenesis and the inhibition of glycolysis.

7 0
4 years ago
Which of the following could be the pH of a very acidic solution?
Ganezh [65]
A. 3

From 0 to 6, a solution is acidic. 7 is neutral and from 8 to 14.. is basic
8 0
3 years ago
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