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il63 [147K]
3 years ago
12

The role of chlorophyll during photosynthesis is to

Chemistry
1 answer:
Fudgin [204]3 years ago
3 0

Answer:

Absorb light energy

Explanation:

Chlorophyll absorbs light energy which is used to produce carbohydrate and oxygen in the presence of carbon dioxide and water.

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The following unbalanced equation illustrates the overall reaction by which the body utilizes glucose to produce energy: C6H12O6
s344n2d4d5 [400]

Answer:

the conversion factor is f= 6  mol of glucose/ mol of CO2

Explanation:

First we need to balance the equation:

C6H12O6(s) + O2(g) → CO2(g) + H2O(l) (unbalanced)

C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) (balanced)

the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:

f = stoichiometric coefficient of CO2 in balanced reaction / stoichiometric coefficient of glucose in balanced reaction

f = 6 moles of CO2 / 1 mol of glucose = 6  mol of glucose/ mol of CO2

f = 6 mol of CO2/ mol of glucose

for example, for 2 moles of glucose the number of moles of CO2 produced are

n CO2 = f * n gluc = 6 moles of CO2/mol of glucose * 2 moles of glucose= 12 moles of CO2

3 0
3 years ago
One atom of silicon can properly be combined in a compound with
Over [174]

your answer is c. two atoms of oxygen.

7 0
3 years ago
Read 2 more answers
Which of the following are evidence that chemical change has occurred
dolphi86 [110]

Answer:

gas given off

Explanation:

that's the answer

3 0
3 years ago
Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. Solutes formula hydroch
matrenka [14]

Compounds which on dissolving in water gets completely dissociates into its ions are known as strong electrolytes whereas compounds which on dissolving in water gets partially dissociates into its ions are known as weak electrolytes.


Substances which gives solution on dissolving in water and do not dissociates into ions also does not conduct electric current are known as nonelectrolyte.

  • Hydrochloric acid, HCl

On adding HCl (strong acid) in water, it will completely dissociates into ions (H^{+} and Cl^{-}) and thus, it is a strong electrolyte.

  • Sodium hydroxide, NaOH

On adding NaOH (strong base) in water, it will completely dissociates into ions (Na^{+} and  OH^{-}) and thus, it is a strong electrolyte.

  • Formic acid, HCOOH

On adding HCOOH (weak acid) in water, it will partially dissociates into ions (H^{+} and  HCOO^{-}) and thus, it is a weak electrolyte.

  • Methyl amine, CH_3NH_2

On adding CH_3NH_2 (weak base) in water, it will partially dissociates into ions (CH_3NH_3^{+} and  OH^{-}) and thus, it is a weak electrolyte.

  • Potassium chloride, KCl

On adding KCl in water, it will completely dissociates into ions (K^{+} and  Cl^{-}) and thus, it is a strong electrolyte.

  • Ethanol, C_2H_5OH

On adding C_2H_5OH in water, it will not dissociates into ions  and thus, it is a nonelectrolyte.

  • Sucrose, C_{12}H_{22}O_{11}

On adding C_{12}H_{22}O_{11} in water, it will not dissociates into ions  and thus, it is a nonelectrolyte.

3 0
3 years ago
In a percentage composition investigation a compound was decomposed into its elements: 20.0 g of calcium, 6.0 g of carbon, and 2
inysia [295]

The percentage composition of this compound : 40%Ca, 12%C and 48%O

<h3>Further explanation</h3>

Given

20.0 g of calcium,

6.0 g of carbon,

and 24.0 g of oxygen.

Required

The percentage composition

Solution

Total mass of compound :

=mass calcium + mass carbon + mass oxygen

=20 g + 6 g + 24 g

=50 g

Percentage composition :

  • Ca-calcium

\tt \dfrac{20}{50}\times 100\%=40\%

  • C-carbon

\tt \dfrac{6}{50}\times 100\%=12\%

  • O-oxygen

\tt \dfrac{24}{50}\times 100\%=48\%

3 0
2 years ago
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