All categories

3 years ago

Find the largest integer which belongs to the following interval: (−∞; 31]

Mathematics

1 answer:

Studentka2010 [4]3 years ago

8 0

Answer:

The largest integer that belongs to the interval (-∞, 31] is 31

Step-by-step explanation:

The given interval is (-∞, 31], from which the round bracket indicates that the number next to the bracket is not included in the inequality while the square [] (closed) bracket indicates that the number next to the bracket is included in the inequality

Therefore, 31 is inclusive in the inequality while -∞ is excluded.

The find the largest integer that belongs to the interval (-∞, 31] the numbers are arranged on the number line as follows

The numbers presented in number line form -∞, .....-1, 0, 1, 2,..., 31

Giving 31 as the largest integer in the inequality

You might be interested in

public accountant financial planner 50.2 48.0 59.8 49.2 57.3 53.1 59.2 55.9 53.2 51.9 56.0 53.6 49.9 49.7 58.5 53.9 56.0 52.8 51

ddd [48]

Using the formula of test statistic, the value of the test statistic is 2.6961.

The mean of the public accountant is

Mean x(p) =50.2+59.8+57.3+59.2+53.2+56.0+49.9+58.5+56.0+51.9/10

x(p) = 55.2

Now the standard deviation of public accountant is

SD(p) = √{∑(x-x(p))^2/n-1}

SD(p) = √(50.2-55.2)^2+(59.8-55.2)^2+..................+(51.9-55.2)^2/n-1

After solving;

SD(p) = 3.34

The mean of the financial planner is

Mean x(F) =48.0+49.2+53.1+55.9+51.9+53.6+49.7+53.9+52.8+48.9/10

x(F) = 51.6

Now the standard deviation of financial planner is

SD(F) = √{∑(x-x(p))^2/n-1}

SD(F) = √(48.0-51.6)^2+(49.2-51.6)^2+..................+(48.9-51.6)^2/n-1

After solving;

SD(F) = 2.57

Test Statistic (t) = $\frac{x(P)-x(f)}{\sqrt{\left(\frac{(n(p)-1)s(p)^2+(n(f)-1)s(f)^2}{n(p)+n(f)-2}\left(\frac{1}{n(p)}+\frac{1}{n(f)}\right)\right)}}$

t = $\frac{55.2-51.61}{\sqrt{\left(\frac{(10-1)(3.34))^2+(10-1)(2.57)^2}{10+10-2}\left(\frac{1}{10}+\frac{1}{10}\right)\right)}}$

After solving

t = 2.6961

Hence, the value of the test statistic is 2.6961.

To learn more about test statistic link is here

brainly.com/question/14128303

#SPJ4

The right question is

public accountant 50.2 59.8 57.3 59.2 53.2 56.0 49.9 58.5 56.0 51.9

financial planner 48.0 49.2 53.1 55.9 51.9 53.6 49.7 53.9 52.8 48.9

Use a 0.05 level of significance and test the hypothesis that there is no difference between the starting annual salaries of public accountants and financial planner

Find the value of the test statistic.

4 0

1 year ago

Determine whether each statement is always, sometimes, or never true. Explain your reasoning. (By the way, this has to do with a

Norma-Jean [14]

A). |x| = |-x|
This is always true.
The definition of 'absolute' value is 'size of the number without its sign'.
That's what this expression says.

b). |x| = -|x|
This is never true, because an absolute value is never negative.
This one would true if x=0 . So maybe some people might say
it's sometimes true, but that doesn't feel right to me. I say never.

c). |-x| = -|x|
This looks to me like exactly the same situation as (b),
and I would say all the same things about it.

6 0

3 years ago

Read 2 more answers

Factor 3x² - 2x + 6

aalyn [17]

Answer:

sorry this does not factor out

Step-by-step explanation:

5 0

3 years ago

Bajo del Gualicho has an elevation of - 72 meters. Lago Enriquillo has an elevation of - 46 meters. Note

Harman [31]

Answer: Bajo del Gualicho has a higher elevation than Lago Enriquillo.

Step-by-step explanation:

Since in this case the "elevations" are negative because are under sea level, we can call it depth.

In this sense, we are given the "elevations" or depths of two places:

Bajo del Gualicho: -72 m

Lago Enriquillo: -46 m

Keeping in mind we are actually talking about the depth of this places, we can say Bajo del Gualicho is deeper than Lago Enriquillo, and this is best expressed with the following inequality:

$G>E$