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Tanya [424]
3 years ago
8

Solve for z -p(d+z) = -2z+59−p(d+z)=−2z+59

Mathematics
1 answer:
alexira [117]3 years ago
6 0

-p(d+z)=-2z+59\qquad\text{use distributive property}\\\\-pd-pz=-2z+59\qquad\text{add pd to both sides}\\\\-pz=-2z+pd+59\qquad\text{add 2z to both sides}\\\\2z-pz=pd+59\\\\z(2-p)=pd+59\qquad\text{divide both sides by}\ (2-p)\neq0\\\\\boxed{z=\dfrac{pd+59}{2-p}}

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Answer:

Step-by-step explanation:

loose (8+5) yards so they lost 13 yards

and obviously they gained 11 yards according to the information given.

5 0
3 years ago
Please help with step by step. Thank you
o-na [289]

Answer:

  • SU = 2
  • PX = 6 2/3

Step-by-step explanation:

The product of distances to the circle along a secant is the same for all secants intersecting a given point.

a. Secants SW and QT intersect at U. Thus ...

  (UT)(UQ) = (US)(UW)

  (1.5)(4) = (SU)(3)

  SU = (4)(1.5)/3

  SU = 2

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b. Secants PT and PX intersect at P. Thus ...

  (PQ)(PT) = (PR)(PX)

  PX = (PQ)(PT)/PR) = (2.5)(2.5 +4 +1.5)/3 = 20/3

  PX = 6 2/3

4 0
3 years ago
An ordinary deck of 52 playing cards is randomly divided into 4 piles of 13 cards example 2g each. compute the probability that
stiks02 [169]
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6 0
3 years ago
At the store, 10 ounces of candy cost $3.20. How many ounces can you get for $1?
mash [69]

Answer:

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8 0
3 years ago
3
adoni [48]

Answer:

The solution set is (5,6).

Step-by-step explanation:

Given equations are:

-6x + 6y= 6         Eqn 1

-6x + 3y=-12      Eqn 2

Subtracting Eqn 2 from Eqn 1

(-6x+6y)-(-6x+3y)= 6-(-12)

-6x+6y+6x-3y=6+12

3y = 18

Dividing both sides by 3

\frac{3y}{3}=\frac{18}{3}\\y=6

Putting y=6 in Eqn 1

-6x+6(6)=6

-6x+36=6

-6x=6-36

-6x=-30

\frac{-6x}{-6}=\frac{-30}{-6}\\x=5

Hence,

The solution set is (5,6).

8 0
3 years ago
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