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Ksivusya [100]
3 years ago
14

Calculate the cost of gasoline for a 420-mile trip if your car averages 20 miles/gallon of gas, and the gas cost 0.95/gallon.

Chemistry
2 answers:
goldenfox [79]3 years ago
8 0

the cost of gas is given as:

$0.95/gallon

the average of car is

20miles / gallon

The distance of trip is 420 miles

Thus the gas consumed for the trip is

Gas consumed = miles covered / car average

gas consumed = 420 / 20 = 21 gallon

The cost of gas will be = total gas consumed X price of each gallon

the cost of gas = 21 X $0.95 =$19.95

iogann1982 [59]3 years ago
3 0

Answer : The cost of gasoline for a 420-mile trip is, $19.95

Solution :

As, 20 mile distance covered by 1 gallon of gas

So, 420 mile distance covered by \frac{420}{20}=21gallon of gas

Now we have to calculate the cost of gasoline.

As, 1 gallon of gas cost = $0.95

So, 21 gallon of gas cost = \$0.95\times 21=\$19.95

Therefore, the cost of gasoline for a 420-mile trip is, $19.95

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Double Displacement reaction

Explanation:

BaCl2 + Na2SO4 → 2NaCl + BaSO4

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3 years ago
At a particular temperature and [A]0 = 2.00 x 10-2 Molar, concentration versus time data were collected for this reaction and a
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3 years ago
What is used to determine the number of each atom in an ionic formula
ladessa [460]

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The charge carried by each ion (oxidation state of each atom)

Explanation:

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3 0
3 years ago
The volume of a sample of gas at 0 degrees Celsius is 100 liters. If the volume of the gas is increased to 200 liters at constan
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Answer:

The answer to your question is: T = 546°K

Explanation:

V1 = 100 l

T1 = 0°C = 273°K

V2 = 200 l

T2 = ?

Pressure = constant

Formula

Charles law  relates volume vs temperature

                                            \frac{V1}{T1} = \frac{V2}{T2}

                                            T2 = \frac{V2T1}{V1}

Substitution

                                             T2 = \frac{(200)(273)}{100}

                                             T2 = \frac{54600}{100}

Result

                                                    T2 = 546°K                      

                                     

4 0
4 years ago
Physical properties include oxidation or tarnishing true or false
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Flammability and corrosion/oxidation resistance are examples of chemical properties

.Tarnishing is properly considered a chemical change.28

BRAINLIEST PLEASE

‍♂❤

GOOD LUCK

5 0
3 years ago
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