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ankoles [38]
3 years ago
11

Draw the product of the following reaction between propanoyl chloride and p-methoxynitrobenzene. Include all formal charges.

Chemistry
2 answers:
Lera25 [3.4K]3 years ago
8 0
Please find the attached document

GREYUIT [131]3 years ago
4 0

Answer:

The product will be :

1-(2-methoxy-5-nitrophenyl)propan-1-one

Explanation:

This is electrophilic substitution reaction.

The electrophile is acylium ion.

The reaction will occur in presence of anhydrous aluminium chloride, which will remove chloride ion and will generate acylium ion which will act as electrophile.

The electrophile will attack on the para or other position of methoxy group.

The mechanism is shown in figure.

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7 0
3 years ago
Read 2 more answers
Write a mechanism for the esterification of propanoic acid with 18O-labeled ethanol. Show clearly the fate of the 18O label. (b)
tatuchka [14]

Answer:

See explanation and images attached

Explanation:

a) In the mechanism for the acid catalysed esterification of propanoic acid using ethanol, we can see that the first step is the protonation of the acid followed by nucleophillic attack of the alcohol. Loss of water and consequent deprotonation regenerates the acid catalyst. We can see the fate of the 18O labelled ethanol in the mechanism shown.

b)  In the second mechanism, an unnamed ester is hydrolysed using an acid catalyst. The attack of the acid and subsequent nucleophillic attack of water labelled with 18O leads to the incorporation of this 18O into the product acid as shown in the mechanism attached to this answer.

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