Draw the product of the following reaction between propanoyl chloride and p-methoxynitrobenzene. Include all formal charges.
2 answers:
Answer:
The product will be :
1-(2-methoxy-5-nitrophenyl)propan-1-one
Explanation:
This is electrophilic substitution reaction.
The electrophile is acylium ion.
The reaction will occur in presence of anhydrous aluminium chloride, which will remove chloride ion and will generate acylium ion which will act as electrophile.
The electrophile will attack on the para or other position of methoxy group.
The mechanism is shown in figure.
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