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3 years ago

You jogged for 2.1 miles, how many feet did you jog?

Chemistry

1 answer:

Fantom [35]3 years ago

6 0

Answer:

11088

Explanation:

you would multiply 2.1 times 5280 bc that is how many feet are in a mile

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To plan ahead using REPS and Checks, choose the minimum space cushion needed to maintain folloying distance traveling at 25 MPH

BaLLatris [955]

The minimum space cushion defines the required amount of space which vehicles should maintain in other to afford them the time and space to gain control in emergency scenarios. Hence, the minimum space cushion required in the scenario is 4 seconds.

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3 years ago

Why is it difficult to collect evidence about the sky

mafiozo [28]

The sky is always changing with new galaxies.

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4 years ago

What metal has the largest atomic radius in period 4 (78 points)

marysya [2.9K]

Answer:

The element potassium(K) with atomic number 19 has the largest atomic radius ( around 225 picometers ).

Explanation:

There is the general expected decrease from left to right with increasing nuclear charge without quantum level expansion or increase in shielding and so pulling the outer electrons closer. The 3d block of metals (Z = 21 to 30) tend to be similar and in fact tend to go through a small minimum at Mn/Fe.

The potassium been on the left most part of period , has largest radius due to least nuclear pulling effect.

6 0

4 years ago

The specific heat capacity of graphite is 0.71 J/°C g.

Tom [10]

Answer:

,,mknlmn

Explanation:

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8 0

3 years ago

A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0- L vessel at 300 K . The following equilibr

umka2103 [35]

Answer:

The concentration of N2 at the equilibrium will be 0.019 M

Explanation:

Step 1: Data given

Number of moles of NO = 0.10 mol

Number of moles of H2 = 0.050 mol

Number of moles of H2O = 0.10 mol

Volume = 1.0 L

Temperature = 300K

At equilibrium [NO]=0.062M

Step 2: The balanced equation

2NO(g) + 2H2(g) → N2(g) + 2H2O(g)

Step 3: Calculate the initial concentration

Concentration = Moles / volume

[NO] = 0.10 mol / 1L = 0.10 M

[H2] = 0.050 mol / 1L = 0.050 M

[H2O] = 0.10 mol / 1L = 0.10 M

[N2] = 0 M

Step 4: Calculate the concentration at the equilibrium

[NO] at the equilibrium is 0.062 M

This means there reacted 0.038 mol (0.038M) of NO

For 2 moles NO we need 2 moles of H2 to produce 1 mol N2 and 2 moles of H2O

This means there will also react 0.038 mol of H2

The concentration at the equilibrium is 0.050 - 0.038 = 0.012 M

There will be porduced 0.038 moles of H2O, this means the final concentration pf H2O at the equilibrium is 0.100 + 0.038 = 0.138 M

There will be produced 0.038/2 = 0.019 moles of N2

The concentration of N2 at the equilibrium will be 0.019 M

5 0

4 years ago