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sweet-ann [11.9K]

3 years ago

12

Suppose that 0.250 mol of methane, CH4(g), is reacted with 0.400 mol of fluorine, F2(g), forming CF4(g) and HF(g) as sole produc

ts. Assuming that the reaction occurs at constant pressure, how much heat is released?

1 answer:

shtirl [24]3 years ago

7 0

300 gallons

Explanation:

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Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

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W are given a chemical reaction:

$Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)$

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To calculate the enthalpy change, we use the formula:

$\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J$

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = $\frac{3283.2J}{0.1326g}=24760.181J/g$

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

$\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol$

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