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arsen [322]
3 years ago
14

To plan ahead using REPS and Checks, choose the minimum space cushion needed to maintain folloying distance traveling at 25 MPH

(for a cargo van)?
Chemistry
1 answer:
BaLLatris [955]3 years ago
3 0

The <em>minimum space cushion</em> defines the required amount of space which vehicles should maintain in other to afford them the time and space to gain control in emergency scenarios. Hence, the minimum space cushion required in the scenario is 4 seconds.

In cases of mishaps or accidents, the space cushion might just afford other cars the space to maneuver their way to safety rather than being caught up in the collison or accident.

The required space cushion in most scenario is usually between 2 - 5 seconds, with additional space afforded depending on the <em>length and type of the vehicle</em>.

Therefore, to ensure safety, the required minimum space cushion to be left when driving being a cargo van traveling at a <em>speed of 25mph is 4 seconds</em>.

Learn more :brainly.com/question/24535523

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Answer these please ASAP need help no idea how to do these
STALIN [3.7K]

Answer:

Explanation:

Cu:

Number of moles = Mass / molar masa

2 mol = mass / 64 g/mol

Mass = 128 g

Mg:

Number of moles = Mass / molar masa

0.5 mol = mass / 24 g/mol

Mass =  g

Cl₂:

Number of moles = Mass / molar masa

Number of moles  = 35.5 g / 24 g/mol

Number of moles = 852 mol

H₂:

Number of moles = Mass / molar mass

8 mol  = Mass / 2 g/mol

Mass =  16 g

P₄:

Number of moles = Mass / molar masa

2 mol  =  mass / 124 g/mol

Mass = 248 g

O₃:

Number of moles = Mass / molar masa

Number of moles  = 1.6 g /48  g/mol

Number of moles = 0.033 mol

H₂O

Number of moles = Mass / molar masa

Number of moles  = 54 g / 18 g/mol

Number of moles = 3 mol

CO₂

Number of moles = Mass / molar masa

2 mol  =  mass / 124 g/mol

Mass = 248 g

NH₃

Number of moles = Mass / molar masa

Number of moles  = 8.5 g / 17 g/mol

Number of moles = 0.5 mol

CaCO₃

Number of moles = Mass / molar masa

Number of moles  = 100 g / 100 g/mol

Number of moles = 1 mol

a)

Given data:

Mass of iron(III)oxide needed = ?

Mass of iron produced = 100 g

Solution:

Chemical equation:

F₂O₃ + 3CO    →    2Fe  + 3CO₂

Number of moles of iron:

Number of moles = mass/ molar mass

Number of moles = 100 g/ 56 g/mol

Number of moles = 1.78 mol

Now we compare the moles of iron with iron oxide.

                        Fe          :           F₂O₃                

                           2          :             1

                          1.78       :        1/2×1.78 = 0.89 mol

Mass of  F₂O₃:

Mass = number of moles × molar mass

Mass = 0.89 mol × 159.69 g/mol

Mass = 142.124 g

100 g of iron is 1.78 moles of Fe, so 0.89 moles of F₂O₃ are needed, or 142.124 g of iron(III) oxide.

b)

Given data:

Number of moles of Al = 0.05 mol

Mass of iodine = 26 g

Limiting reactant = ?

Solution:

Chemical equation:

2Al + 3I₂   →  2AlI₃

Number of moles of iodine = 26 g/ 254 g/mol

Number of moles of iodine = 0.1 mol

Now we will compare the moles of Al and I₂ with AlI₃.

                          Al            :         AlI₃    

                          2             :           2

                         0.05         :        0.05

                           I₂            :         AlI₃

                           3            :          2

                         0.1           :           2/3×0.1 = 0.067

Number of moles of AlI₃ produced by Al are less so it will limiting reactant.

Mass of AlI₃:                            

Mass = number of moles × molar mass

Mass = 0.05 mol × 408 g/mol

Mass = 20.4 g

26 g of iodine is 0.1 moles. From the equation, this will react with 2 moles of Al. So the limiting reactant is Al.

c)

Given data:

Mass of lead = 6.21 g

Mass of lead oxide = 6.85 g

Equation of reaction = ?

Solution:

Chemical equation:

2Pb + O₂   → 2PbO

Number of moles of lead = mass / molar mass

Number of moles = 6.21 g/ 207 g/mol

Number of moles = 0.03 mol

Number of moles of lead oxide = mass / molar mass

Number of moles = 6.85 g/ 223 g/mol

Number of moles = 0.031 mol

Now we will compare the moles of oxygen with lead and lead oxide.

               Pb         :        O₂

                2          :         1

               0.03     :      1/2×0.03 = 0.015 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.015 mol × 32 g/mol

Mass =  0.48 g

The mass of oxygen that took part in equation was 0.48 g. which is 0.015 moles of oxygen. The number of moles of Pb in 6.21 g of lead is 0.03 moles. So the balance equation is

2Pb + O₂   → 2PbO

   

6 0
3 years ago
What is nuclear medicine
Mumz [18]
The branch of medicine that deals with the use of radioactive substances in research, diagnosis, and treatment.
6 0
3 years ago
Read 2 more answers
Hey I need help with this element, compound, and mixtures worksheet
Alika [10]

We should describe a little bit the legend.

A - Element - we should have circles with same color and not bonded together (argon gas).

B - Compound - here we may have circles with same or different color bonded together (water or oxygen which is a diatomic molecule).

C - Mixture of elements - circles with different colors not not bonded together (mixture of noble gases).

D - Mixture of compounds - circles with same or different color bonded together but we should see two or more types of connectivity between circles (mixture of water and ethanol).

E - Mixture of elements and compounds - circles with same or different color bonded together mixed with circles with same color and not bonded together (a mixture between oxygen which is a diatomic molecule and noble gas like argon).

Now we may answer the question:

1) B

2) C

3) D

4) D

5) A

6) B

7) B

8) E

9) E

10) D

11) B

12) D

13) D

14) D

15) D

7 0
3 years ago
How did Fizeau prove or disprove Galileo’s findings?
Elis [28]

Answer:

It is commonly believed that the Catholic Church persecuted Galileo for abandoning ... Thus Galileo did not prove the theory by the Aristotelian standards of science in his day. ... If we believe Relativity, science never *can* disprove them. ... If you correctly report the findings of Fr. Spitzer, then he is wrong.

Explanation:

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6 0
3 years ago
if a solution containing 75 mL of alcohol has a percent by volume of 50%, what is the total volume of the solution
Ad libitum [116K]

Answer:

150.0 mL.

Explanation:

  • Volume percent is the ratio of the solute volume to the solution volume multiplied by 100.

∵ V% = (V of solute/V of solution) x 100.

<em>∴ V of solution = (V of solute/V%) x 100</em> = (75 mL/50) x 100 = <em>150.0 mL.</em>

5 0
3 years ago
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