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statuscvo [17]
2 years ago
13

In fish or flaxseed the best source of omega3 fatty acids? Why?

Biology
1 answer:
Katena32 [7]2 years ago
3 0
Fish because it is full of healthy oils. But depends on the kind of fish. I know salmon is rich in omega 3 fa
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Help with question 2 and 3 please
aleksandr82 [10.1K]

Answer:

b and d i think

Explanation:

8 0
3 years ago
In part A, you analyzed genes that contribute to two diseases. How can scientists use this information to develop new treatments
Sergeeva-Olga [200]

Answer:

Yes scientist will need to develop multiple treatments to control symptoms.

Explanation:

because if they only do one treatment it may not work for everyone because some people could be allergic to that one treatment that's why there are multiple treatments.

8 0
2 years ago
In the Calvin cycle, which of the following best describes the sources of the elements that combine to make sugar?
stiks02 [169]
I think your answer would be c
3 0
3 years ago
22) moves using an undulating membrane connected to a flagellum
Marrrta [24]

The answer is “Trypanosoma”. The word “Trypanosoma” comes from the Greek words trypanon and soma, which means auger and body, or auger body. A Trypanosoma moves through an undulating membrane connected to a flagellum. Trypanosoma comes from a genus of kinetoplastids, it is known to be a monophyletic cluster of single-celled parasitic flagellate protozoa. 

8 0
3 years ago
Assume that you have 1 mL of a solution of amylase (an enzyme) at a concentration of 15 mg protein/mL. Calculate the volume of d
lidiya [134]

Answer:

42,5 mL

Explanation:

We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.

DF=\frac{Vi}{Vf}

<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>

The first step is to have the same measurment unit so we need to convert 345 µg to mg.

we know that 1 µg equals 0,001 g, hence:

345 µg = 0,345 mg

now the final volume is 0,345 mg  protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula

DF= \frac{15mg protein/mL}{0.345mg protein/mL}

DF= 43,5 mg protein/ mL

Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL

43,5mL-1,0mL = 42,5 mL

So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)

8 0
3 years ago
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