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svet-max [94.6K]
3 years ago
10

What is the equation of this line? y=12x−3 y=−12x−3 y=−2x−3 y=2x−3 Number graph ranging from negative 5 to 5 on both the x and y

axis. A line passes through the point begin ordered pair 0 comma negative 3 end ordered pair and the point begin ordered pair 4 comma negative 1 end ordered pair
Mathematics
2 answers:
Tems11 [23]3 years ago
5 0

We are given that

A line passes through two  points as

(0,-3)  and (4,-1)

(x_1,y_1)=(0,-3)

x_1=0,y_1=-3

(x_2,y_2)=(4,-1)

x_2=4,y_2=-1

Firstly, we can find slope

m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug values

m=\frac{-1+3}{4-0}

m=\frac{2}{4}

m=\frac{1}{2}

now, we can use point  slope form of line

y-y_1=m(x-x_1)

we can plug values

y+3=\frac{1}{2} (x-0)

y+3=\frac{1}{2}x

y=\frac{1}{2}x-3

so, the equation of line is

y=\frac{1}{2}x-3...............Answer


algol [13]3 years ago
5 0

Answer:

y = -2/3x +2

Step-by-step explanation:

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