Consider the circumscribed angle. value of x

Is it yes or no if yes can you please explain it

Answer:

No, these triangles are not similar.

Step-by-step explanation:

Similar triangles have the same angle measures.

Knowing that the angles in a triangle add up to 180 degrees, find the missing angle, and you will see that the angles in the triangle are not congruent to each other, meaning that the triangles are not similar.

6 0

3 years ago

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The computers of six faculty members in a certain department are to be re- placed. two of the faculty members have selected lapt

FinnZ [79.3K]

Answer:

A) The probability that both selected setups are for laptop computers is 0.067

B)The probability that both selected setups are desktop machines is 0.4

C)The probability that at least one selected setup is for a desktop computer is 0.933

D)The probability that at least on computer of each type is chosen for setup is 0.533

Step-by-step explanation:

Number of laptops = 2

Number of desktops = 4

Total number of outcomes = 15

a) what is the probability that both selected setups are for laptop computers?

Total number of outcomes = 15

So, the probability that both selected setups are for laptop computers = $\frac{1}{15}=0.067$

b)what is the probability that both selected setups are desktop machines?

Number of desktops = 4

Number of desktops to be chosen = 4

We will use combination

No. of ways to select two desktops = $^4C_2=\frac{4!}{2!(4-2)!}=6$

So,the probability that both selected setups are desktop machines= $\frac{6}{15}=0.4$

(c) what is the probability that at least one selected setup is for a desktop computer?

P(at least 1 desktop)=1-P(No desktop)

P(at least 1 desktop)=1-P(both laptops)

P(at least 1 desktop)=1-0.067=0.933

So,the probability that at least one selected setup is for a desktop computer is 0.933

d) what is the probability that at least on computer of each type is chosen for setup?

No. of ways to select one desktop $=^4C_1=\frac{4!}{1!(4-1)!}=4$

No. of ways to select one laptop = $^2C_1=\frac{2!}{1!(2-1)!}=2$

So, No. of ways to select one laptop and one desktop= $4 \times 2 = 8$

So,the probability that at least on computer of each type is chosen for setup= $\frac{8}{15}=0.533$

6 0

3 years ago

Hai has $100 available to buy USB drives to back up data for his business computers. Each USB drive has a price of $8, and Hai w

lana66690 [7]

Answer:

11

Step-by-step explanation:

4 0

3 years ago

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At a factory that produces pistons for cars, Machine 1 produced satisfactory pistons and unsatisfactory pistons today. Machine 2

ryzh [129]

I suspect that there's supposed to be a number before each "satisfactory" and each "unsatisfactory", and I'm pretty sure that none of them is there. The question, exactly as it's written, can't be answered.

7 0

4 years ago

Can you please help me with this

Rina8888 [55]

The formula to find the volume multiplies the length by the width by the height, so length is 7, the width is 2 and the height is 3.

7×2×3= 42

42 cubic units.

7 0

3 years ago

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Consider the circumscribed angle. value of x ​

Consider the circumscribed angle. value of x