Consider the circumscribed angle. value of x

Are words even real is anything we as humans taught real in life is it lies please answer with your own thoughts

den301095 [7]

Technically, everything we know was made up by our own minds. We thought of it all. We decided that the color of the sky would be called "blue" and not "doorknob". Education is a continuous cycle that never stops progressing.

6 0

3 years ago

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What is the area of a circle with a radius of 6 inches?

Vika [28.1K]

Answer:

The answer to your question is 113.04 in²

Step-by-step explanation:

To solve this problem substitute the values in the formula and simplify.

Data

Area = ?

radius = 6 in

π = 3.14

Formula

Area = π x r²

Substitution

Area = (3.14) x (6)²

Simplification

Area = 3.14 x 36

Result

Area = 113.04 in²

7 0

3 years ago

Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE

inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to $20\ units$

Part 3) The area is equal to $25\ units^{2}$

Step-by-step explanation:

we have

$A(5,0), B(2,4), C(-2,1),D(1,-3)$

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(5,0),B(2,4)$

substitute in the formula

$d=\sqrt{(4-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$AB=5\ units$

Find the distance BC

$B(2,4), C(-2,1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$BC=5\ units$

Find the distance CD

$C(-2,1),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-4)^{2}+(3)^{2}}$

$d=\sqrt{25}$

$CD=5\ units$

Find the distance AD

$A(5,0),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(1-5)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$AD=5\ units$

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

$B(2,4),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-4)^{2}+(1-2)^{2}}$

$d=\sqrt{(-7)^{2}+(-1)^{2}}$

$BD=\sqrt{50}\ units$

Verify if the polygon is a square

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

$BD^{2}=AD^{2}+AB^{2}$

substitute

$(\sqrt{50})^{2}=5^{2}+5^{2}$

$50=50$ -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

Find the Area of the polygon

The area of a square is equal to

$A=b^{2}$

we have

$b=5\ units$

$A=5^{2}=25\ units^{2}$

Find the perimeter of the polygon

The perimeter of a square is equal to

$P=4b$

we have

$b=5\ units$

$P=4(5)=20\ units$

6 0

3 years ago

What is 1 + 1 ???? thank you next (;

Step2247 [10]

Answer: 2

Step-by-step explanation:

1 + 1 = 2

5 0

3 years ago

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Solve for x x-4=-7. Please

Alecsey [184]

Answer:

-3

Step-by-step explanation:

x - 4 = - 7

Carry over the - 4 and make x the subject.

x= - 7 + 4

x= - 3

Therefore x is - 3

8 0

4 years ago

Consider the circumscribed angle. value of x ​

Consider the circumscribed angle. value of x