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4 years ago

Can you plz help me ?! It's urgent for today's homework

Mathematics

2 answers:

kotykmax [81]4 years ago

3 0

18 cards
Hope it helps!

alexdok [17]4 years ago

3 0

18 cards were baseball cards

48÷8=6
6×3=18

hope this helped

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On a map, ½ inch represents 200 miles. How long would a line on a map need to be in order to represent 1800 miles?

givi [52]

9 because 1,800 divided by 200 is 9

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3 years ago

(If this question is easy, I am just horrible with percentages, lol :p)

Sati [7]

55% of 20 is 11. the answer is 20

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3 years ago

27 (x2+8x+16) / 3 (x2+6x+8) simplify

Karolina [17]

Answer:

9x4+126x3+648x2+1440x+1152

Step by step:

27(x^2+8x+16) / 3 (x^2+6x+8)

(27(x^2+8x+16) / 3) (x^2+6x+8)

(27(x^2+8x+16) / 3) (x^2) +(27(x2+8x+16) / 3) (6x)+(27(x2+8x+16)/3) (8)

9x4+72x^3+144x^2+54x^3+432x^2+864x+72x^2+576x+1152

9x4+126x3+648x2+1440x+1152

3 0

3 years ago

2 questions in one.<br> Help?..

daser333 [38]

Answer:

2. 3

3. 4^45

Step-by-step explanation:

${ ({5}^{4} ) }^{m} = {5}^{12} \\ = > {5}^{4m} = {5}^{12} \\ = > 4m = 12 \\ = > m = \frac{12}{4} \\ = > m = 3 \\ \\ number \: of \: books \: at \: library \\ = {({4}^{9})}^{5} \times {4}^{0} \\ = {4}^{45} \times 1 \\ = {4}^{45}$

4 0

3 years ago

Read 2 more answers

Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an

Lorico [155]

Answer:

P(Z < 2.37) = 0.9911.

Step-by-step explanation:

We are given that Let z denote a random variable that has a standard normal distribution.

Let Z = a random variable

So, Z ~ Standard Normal(0, 1)

As we know that the standard normal distribution has a mean of 0 and variance equal to 1.

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean = 0

$\sigma$ = standard deviation = 1

Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)

P(Z < 2.37) = P(Z < $\frac{2.37-0}{1}$ ) = P(Z < 2.37) = 0.9911

The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.

4 0

3 years ago