All categories

4 years ago

2 A kovács a meleg vasat a hideg vízbe teszi. A vas

Physics

1 answer:

Anton [14]4 years ago

4 0

Answer:

300 kJ

Explanation:

There are two energy flows in this process.

Heat lost by iron + heat gained by water = 0

q₁ + q₂ = 0

-300 kJ + q₂ = 0

q₂ = 300 kJ

The water gained 300 kJ.

You might be interested in

Help me please (*￣(ｴ)￣*)

Len [333]

Answer:

1) Are always conservative

Explanation:

Elastic forces are always conservative.

Hope it helps you.

please mark as the brainliest answer.

3 0

3 years ago

Read 2 more answers

Zero, a hypothetical planet, has a mass of 5.3 x 1023 kg, a radius of 3.3 x 106 m, and no atmosphere. A 10 kg space probe is to

Goryan [66]

(a) $3.1\cdot 10^7 J$

The total mechanical energy of the space probe must be constant, so we can write:

$E_i = E_f\\K_i + U_i = K_f + U_f$ (1)

where

$K_i$ is the kinetic energy at the surface, when the probe is launched

$U_i$ is the gravitational potential energy at the surface

$K_f$ is the final kinetic energy of the probe

$U_i$ is the final gravitational potential energy

Here we have

$K_i = 5.0 \cdot 10^7 J$

at the surface, $R=3.3\cdot 10^6 m$ (radius of the planet), $M=5.3\cdot 10^{23}kg$ (mass of the planet) and m=10 kg (mass of the probe), so the initial gravitational potential energy is

$U_i=-G\frac{mM}{R}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{3.3\cdot 10^6 m}=-1.07\cdot 10^8 J$

At the final point, the distance of the probe from the centre of Zero is

$r=4.0\cdot 10^6 m$

so the final potential energy is

$U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{4.0\cdot 10^6 m}=-8.8\cdot 10^7 J$

So now we can use eq.(1) to find the final kinetic energy:

$K_f = K_i + U_i - U_f = 5.0\cdot 10^7 J+(-1.07\cdot 10^8 J)-(-8.8\cdot 10^7 J)=3.1\cdot 10^7 J$

(b) $6.3\cdot 10^7 J$

The probe reaches a maximum distance of

$r=8.0\cdot 10^6 m$

which means that at that point, the kinetic energy is zero: (the probe speed has become zero):

$K_f = 0$

At that point, the gravitational potential energy is

$U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{8.0\cdot 10^6 m}=-4.4\cdot 10^7 J$

So now we can use eq.(1) to find the initial kinetic energy:

$K_i = K_f + U_f - U_i = 0+(-4.4\cdot 10^7 J)-(-1.07\cdot 10^8 J)=6.3\cdot 10^7 J$

4 0

3 years ago

A cubical gaussian surface surrounds a long, straight, charged filament that passes perpendicularly through two opposite faces.

laiz [17]

Answer:

The electric flux is zero through four cube surfaces given that a cubical gaussian surface surrounds a long, straight, charged filament that passes perpendicularly through two opposite faces.

Explanation:

Assuming the charged filament is quite long and you are not near the edges, the two opposing sides that the filament travels through have no flux. If the charge filament is long, which you may assume is indefinitely long, then there is the equal amount of charge on the left and right of where you are, therefore the electric field has no preference for left or right. This implies that the electric field can only travel in or out of the filament. No field lines run through the two faces of the cube that the filament goes through if the electric field is not moving left or right. There are electric field lines on the four sides of the filament.

To learn more about cubical gaussian surface and electric flux. Click brainly.com/question/13003911

#SPJ4

7 0

2 years ago

If a graduated cylinder has a current water level of 30 ml and you add an object which causes the water level to rise to 53 ml,

Katen [24]

Answer:

23L

Explanation:

Given that:

Initial volume of water = 30mL

Final volume of water after an object was placed on it = 53mL

The volume object added which resulted in a rise to 5mL will be :

Final Volume of object - Initial volume of object

53 mL - 30mL = 23mL

Hence, volume of object added is 23 mL

5 0

3 years ago

What is the correct name for this formula: SiO2?

Brrunno [24]

Silicon Dioxide is the answer

6 0

4 years ago

Read 2 more answers