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labwork [276]
3 years ago
9

1. A densidade do nitrogênio nas condições normais de temperatura e pressão é igual a 1,24507 kg/m³. Qual a massa de 200 cm³ de

nitrogênio em lbm?
Physics
1 answer:
Levart [38]3 years ago
3 0

Answer:

5.49×10⁻⁴ lbm

Explanation:

Convert volume to m³.

V = (200 cm³) (1 m / 100 cm)³ = 0.0002 m³

Find mass in kg.

m = ρV

m = (1.24507 kg/m³) (0.0002 m³)

m = 0.000249 kg

Convert mass to lbm.

m = (0.000249 kg) (2.205 lbm/kg)

m = 0.000549 lbm

m = 5.49×10⁻⁴ lbm

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A student is performing experiments on a particular substance. Which
boyakko [2]

Answer: A.

Explanation:

6 0
2 years ago
A polarized light that has an intensity I0 = 60.0 W/m² is incident on three polarizing disks whose planes are parallel and cente
nikitadnepr [17]

Answer:

The transmitted intensity through all polarizers is I_3 =41.31 W/m^2

Explanation:

 According to Malu's law the intensity of a polarized light having an initial intensity I_0 is mathematically represented as

               I = I_0cos^2 \theta

Now  considering the polarizer(The polarizing disk) the equation above becomes

          I = I_0 (cos^2 \theta)^n

Where n is the number of polarizers

       Substituting  60.0W/m^2 for the initial intensity 3 for the n and 20° for the angle of rotation

           I_3 = 60 (cos^220)^3

               =41.31 W/m^2

             

     

                         

6 0
3 years ago
I'm pretty sure it's density but I need another opinion.
bixtya [17]
I agree with density
6 0
3 years ago
Read 2 more answers
1.How long dose long term alcohol abuse affect the liver ?
Agata [3.3K]
1. B- it can cause cirrhosis
2. C- intoxication
3. A- admit to having a problem with alcohol
4. D- binge-drinking
5. A- depressant
6. true
7. false
7 0
3 years ago
Read 2 more answers
A 30-mm-diameter copper rod is 1 m long with a yield strength of 70 MPa. Determine the axial force necessary to cause the diamet
ivolga24 [154]

Explanation:

Given data:

d = 30 mm = 0.03 m

L = 1m

S_{y} = 70 Mpa

Δd = -0.0001d

Axial force = ?

validity of elastic deformation assumption.

Solution:

O'₂ = Δd/d = (-0.0001d)/d = -0.0001

For copper,

v = 0.326      E = 119×10³ Mpa

O'₁ = O'₂/v = (-0.0001)/0.326 = 306×10⁶

∵δ = F.L/E.A    and σ = F/A so,

σ = δ.E/L = O'₁ .E = (306×10⁻⁶).(119×10³) = 36.5 MPa

F = σ . A = (36.5 × 10⁻⁶) . (π/4 × (0.03)²) = 25800 KN

S_{y} = 70 MPa > σ = 36.5 MPa

∵ elastic deformation assumption is valid.

so the answer is

F = 25800 K N            and     S_{y} > σ

3 0
3 years ago
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