All categories

2 years ago

A miner of mass 90kg travels down a slide calculate the potential energy of the miner when he moves15m vertically downwards

Physics

1 answer:

Lena [83]2 years ago

8 0

Answer:

Gravitational Potential Energy = mgh

Explanation:

As the miner moves down, the GPE changes because the height changes.

Gravitational Potential Energy = mgh

You might be interested in

Tamsin strikes a golf ball so that it flies off with a speed of 60 m/s. The golf ball has a mass of 45 g. Calculate the kinetic

hram777 [196]

81 joule is the kinetic energy of the golf ball.

K.E= mv²/2

K.E=0.045×60×60÷2

K.E=81 joule

Kinetic energy is a particular kind of power that is present in moving particles or objects. An object gains kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force. Kinetic energy is a property of motion that depends on the mass and speed of an object or particle. Motion is any combination of vibration, axis rotation, translation, and movement (along a path from one location to another). A body's translational kinetic energy, which is determined by multiplying its mass, m, by the square of its speed, v, is equal to 1/2mv2.

To know more about kinetic energy visit : brainly.com/question/14838079

#SPJ4

7 0

7 months ago

What are the body measurements

ki77a [65]

Answer:

body measurements are a common method specifying body proportion for the purpose of fitting clothes.

6 0

2 years ago

Read 2 more answers

A spring has a natural length of 0.5 m and was stretched by 0.02 m. if the spring had a resultant energy of 0.5 j what is the sp

Anna71 [15]

$\textbf{2500 }\dfrac{\textbf{kg}}{\textbf{s}^{\textbf{2}}}$

Explanation:

Natural length of a spring is $0.5\text{ }m$ . The spring is streched by $0.02\text{ }m$ . The resultant energy of the spring is $0.5\text{ }J$ .

The potential energy of an ideal spring with spring constant $k$ and elongation $x$ is given by $\dfrac{1}{2}kx^{2}$ .

So, in the current problem, the natural length of the spring is not required to find the spring constant $k$ .

$\text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}$

∴ The spring constant of the spring = $2500\text{ }\frac{kg}{s^{2}}$

4 0

3 years ago

So far, you’ve been working with an "ideal" pulley system. How do you think real pulley systems are different, and how would tha

almond37 [142]

Answer:

In an ideal pulley system is assumed as a perfect system, and the efficiency of the pulley system is taken as 100% such that there are no losses of the energy input to the system through the system's component

However, in a real pulley system, there are several means through which energy is lost from the system through friction, which is converted into heat, sound, as well as other forms of energy

Given that the mechanical advantage = Force output/(Force input), and that the input force is known, the energy loss comes from the output force which is then reduced, and therefore, the Actual Mechanical Advantage (AMA) is less than the Ideal Mechanical Advantage of an "ideal" pulley system

The relationship between the actual and ideal mechanical advantage is given by the efficiency of the pulley system as follows;

$Efficiency \, \% = \dfrac{AMA}{IMA} \times 100$

Explanation:

8 0

2 years ago

A 50 Ohm resistance causes a current of 5 milliamps to flow through a circuit connected to a battery. What is the power in the c

UkoKoshka [18]

Answer:0.00125 watts

Explanation:

resistance=50 ohms

Current=5 milliamps

Current=5/1000 milliamps

Current =0.005 amps

power=(current)^2 x (resistance)

Power=(0.005)^2 x 50

Power=0.005 x 0.005 x 50

Power=0.00125 watts

8 0

2 years ago

Read 2 more answers