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Arte-miy333 [17]
4 years ago
10

Reactions occur within the sun to transform what energy into what energy

Chemistry
1 answer:
scoundrel [369]4 years ago
8 0

Answer:

Chemical energy to light and thermal energy.

Explanation:

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Concept map of MATTER - can be a substance- can be a
frez [133]

Substance - Elements and Compounds

Example of element is oxygen and that of compound is water.

Matter can be classified into mixture.

It can be heterogeneous and homogenous.

Example of heterogeneous mixture is milk.

Example of homogeneous mixture is air.

Please mark me Brainliest

3 0
3 years ago
In terms of electrons, what happens when Cations bond with anions?
Black_prince [1.1K]

Answer:

when an atom, typically a metal, loses an electron or electrons, and becomes a positive ion, or cation. Another atom, typically a non-metal, is able to acquire the electron(s) to become a negative ion, or anion.

Explanation:

4 0
2 years ago
a mixture of oxygen, hydrogen, and nitrogen gases exerts a total pressure of 282 kpa. if the partial pressures of oxygen and hyd
dimaraw [331]
Pressures oxygen and hydrogen +  pressure nitrogen

110 Kpa + 106 Kpa = 216 Kpa

Partial pressure:

total pressure -  exerted by nitrogen:

282 Kpa - 216 Kpa

= 66 Kpa

hope this helps!
7 0
3 years ago
Read 2 more answers
How many hybrid orbitals are found in CCl4? o one o two o three o four​
BlackZzzverrR [31]

Answer:

I Believe it is 4 orbitals s,p,p,p or aka sp^3

Explanation:

4 0
3 years ago
Read 2 more answers
At 400 K, This Reaction Has Kp 8.2 X 104 What Is Kp At 400 K For The Following Reaction
kondor19780726 [428]

The given question is incomplete, here is a complete question.

At 400 K, this Reaction has K_p=8.2\times 10^{-4}

SO_3(g)\rightleftharpoons SO_2(g)+\frac{1}{2}O_2(g)

What Is K_p at 400 K for the following reaction?

2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)

(A) 8.2 x 10⁻⁴

(B) 2.9 x 10⁻²

(C) 6.7 x 10⁻⁷

(D) 1.6 x 10⁻⁷

Answer : The correct option is, (C) 6.7\times 10^{-7}

Explanation :

The given chemical equation follows:

SO_3(g)\rightleftharpoons SO_2(g)+\frac{1}{2}O_2(g)

The equilibrium constant for the above equation, K_p=8.2\times 10^{-4}.

We need to calculate the equilibrium constant for the following equation of above chemical equation, which is:

2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g),   K_p'

The equilibrium constant for the doubled reaction will be the square of the initial reaction.

Or, we can say that

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

The value of equilibrium constant for the following reaction is:

K_{p}'=(K_p)^2

K_{p}'=(8.2\times 10^{-4})^2

K_{p}'=6.7\times 10^{-7}

Hence, the value of equilibrium constant for the following reaction is, 6.7\times 10^{-7}

7 0
3 years ago
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