Question

a mixture of oxygen, hydrogen, and nitrogen gases exerts a total pressure of 282 kpa. if the partial pressures of oxygen and hydrogen are 110 kpa and 106 kpa respectively, what is the partial pressure exerted by nitrogen?

Answer 1

Answer :  The partial pressure of $N_2$ is, 66 Kpa

Solution :

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

$P_T=p_{N_2}+p_{O_2}+p_{H_2}$

where,

$P_T$ = total partial pressure = 282 Kpa

$P_{N_2}$ = partial pressure of nitrogen = ?

$P_{O_2}$ = partial pressure of oxygen = 110 Kpa

$P_{H_2}$ = partial pressure of hydrogen = 106 Kpa

Now put all the given values is expression, we get the partial pressure of the nitrogen gas.

$282Kpa=p_{N_2}+110Kpa+106Kpa$

$p_{N_2}=66Kpa$

Therefore, the partial pressure of $N_2$ is, 66 Kpa

Answer 2

Pressures oxygen and hydrogen +  pressure nitrogen

110 Kpa + 106 Kpa = 216 Kpa

Partial pressure:

total pressure -  exerted by nitrogen:

282 Kpa - 216 Kpa

= 66 Kpa

hope this helps!