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2 years ago

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Cellular respiration involves the use of oxygencarbon dioxide and the release of carbon dioxideoxygen

2 answers:

Ghella [55]2 years ago

5 0

cellular respiration involves the use of oxygen and release carbon dioxide.

Reil [10]2 years ago

3 0

Cellular respiration can be thought of as the opposite of photosynthesis. In cellular respiration oxygen is turned into carbon dioxide while in photosynthesis carbon dioxide is tuned to oxygen.

I hope this helps. let me know in the comments if anything is unclear.

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An oxygen atom has a mass of 2.66 x 10^-23 g and a glass of water has a mass of 0.050kg. Use this information to answer the ques

fomenos

<h2>ANSWER OF EACH PART ARE GIVEN BELOW</h2>

Explanation:

A)

We know, each mole contains $N_A=$ $6.023 \times 10^{23}$ atoms.

It is given that mass of one oxygen atom is m= $2.66\times 10^{-23}\ g$ .

Therefore, mass of one mole of oxygen, $M=m\times N_A$ .

Putting value of n and $N_A$ ,

$M=2.66\times 10^{-23}\times 6.023\times 10^{23} \ gm\\M=16.0\ gm$

B)

Given,

Mass of water in glass=0.050 kg = 50 gm.

From above part mass of one mole of oxygen atoms = 16.0 gm.

Therefore, number of mole of oxygen equivalent to 50 gm oxygen $=\dfrac{50}{16}=3.1 \ moles.$

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Avogadro's number

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2 years ago

Help me please I need to pass my exam

Troyanec [42]

Answer:

I think it is 1115 kJ but I don't see the answer

Explanation:

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3 years ago

A compound has a molar mass of 90. grams per mole and the empirical formula CH2O. What is the molecular formula of this compound

Elanso [62]

The molecular formula of this compound is C3H603 XD

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3 years ago

19. This type of bond involves the bonding of two ions of opposite charges

hammer [34]

Answer:

Covalent bond is a type of bond involves the bonding of two ions of opposite charges.

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u><u>.</u></h3>

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2 years ago

A 49.48-mL sample of an ammonia solution is analyzed by titration with HCl. It took 38.73 mL of 0.0952 M HCl to titrate the ammo

Kryger [21]

Answer:

M₂ = 0.0745 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = 0.0952 M

V₁ = 38.73 mL

M₂ = ?

V₂ = 49.48 mL

Using the above formula , the molarity of ammonia , can be calculated as ,

M₁V₁ = M₂V₂

0.0952 M * 38.73 mL = M₂* 49.48 mL

M₂ = 0.0745 M

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3 years ago