It's B. by identifying the elements.
Reasons:
prefixes are only used for covalent compounds.
You don't include the number of atoms when you write the chemical name of a compound.
Subscripts are basically numbers that tell how many atoms of each element is in a compound. It does not identify the name of an element.
Answer:
18 g is the mass produced by 4 g of H₂ and 16 g of O₂
Explanation:
The reaction is:
2H₂ + O₂ → 2H₂O
So, let's find out the limiting reactant as we have both data from the reactants.
Mass / Molar mass = moles
4 g/ 2g/m = 2 moles H₂
16g / 32 g/m = 0.5 moles O₂
2 moles of hydrogen react with 1 mol of oxygen, but I have 0.5, so the O₂ is the limiting.
1 mol of O₂ produces 2 mol of water.
0.5 mol of O₂ produce (0.5 .2)/1 = 1 mol of water.
1 mol of water weighs 18 grams.
Answer:
carbon
Explanation:
Carbon forms compounds that make up about 18 percent of all the matter in living things. The processes by which organisms consume carbon and return it to their surroundings constitute the carbon cycle.
Answer:
Sodium Carbonate
Explanation:
Washing Soda�Sodium Carbonate (Na2CO3) (Na = Sodium, water softening)
Sodium softens water by binding with Calcium and Magnesium forming solid, which can be rinsed off the fabric. �However, if not rinsed thoroughly, the minerals can redeposit onto the fabric and cause problems. �
Answer:
![\frac{[F^{-}]}{[HF]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BF%5E%7B-%7D%5D%7D%7B%5BHF%5D%7D)
is larger
Explanation:
, where 
is the acid dissociation constant.
For a monoprotic acid e.g. HA, ![K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}](https://tex.z-dn.net/?f=K_%7Ba%7D%3D%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
and ![\frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D%3D%5Cfrac%7BK_%7Ba%7D%7D%7B%5BH%5E%7B%2B%7D%5D%7D)
So, clearly, higher the value , lower will the the 
In this mixture, at equilibrium, ![[H^{+}]](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D)
will be constant.
of HF is grater than of HCN
Hence, ![(\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})](https://tex.z-dn.net/?f=%28%5Cfrac%7BF%5E%7B-%7D%7D%7B%5BHF%5D%7D%3D%5Cfrac%7BK_%7Ba%7D%28HF%29%7D%7B%5BH%5E%7B%2B%7D%5D%7D%29%3E%28%5Cfrac%7BCN%5E%7B-%7D%7D%7B%5BHCN%5D%7D%3D%5Cfrac%7BK_%7Ba%7D%28HCN%29%7D%7B%5BH%5E%7B%2B%7D%5D%7D%29)
So, is larger
