1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
never [62]
3 years ago
5

It takes a boat 3 hours to travel 45 miles downstream and 4 hours to travel 44 miles upstream.

Mathematics
1 answer:
krok68 [10]3 years ago
6 0

Answer:

2 miles per hour

Step-by-step explanation:

We use the distance formula. D = r * t

45/3 = 15 mph | Trip 1 |

44/4= 11mph | Trip 2 |

15-11 = 4 mph difference traveling upstream or downstream. Thus the speed of the current is 2 miles per hour.

You might be interested in
What's greater 27 oz or 2 Ib
Sholpan [36]
2 lbs, if you make the oz into lbs, it makes 32 pounds which is greater than 27.
5 0
3 years ago
Read 2 more answers
Two mechanics worked on a car. The first mechanic worked for 15
nevsk [136]

Answer: For the sum of 130

First: $90

Second: $40

Step-by-step explanation:

We write equations for each part of this situation.

<u>The Total Charge</u>

Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.

<u>The Sum of the Rates</u>

Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.

We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.

For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.

15a + 5 (130-a)=1550

15a+650-5a=1550

10a+650-650=1550-650

10a=900

a=$90 was charged by the first mechanic.

We substitute to find the second mechanic's rate.

90+b=130

90-90+b=130-90

b= $40 was charged by the second mechanic

5 0
3 years ago
Chloe is paid $1,213.15 semimonthly. What is her average monthly net, or take-home, pay?
77julia77 [94]
HI THERE
36390
HOPE THAT HELPS

8 0
3 years ago
Read 2 more answers
C) If the spinner is spun another 1000 times,
trapecia [35]

Answer:

130

Step-by-step explanation:

<u>Probability of green:</u>

  • P= 39/300

<u>Number of attempts:  </u>

  • 1000

<u>Expected number of landing on green: </u>

  • <em>Expected frequency = probability × number of trials</em>
  • 1000*39/300 = 130 times

<u>Answer: </u>130 times

7 0
4 years ago
If six angles of a heptagon have measures of 122, 153, 168, 105, 162, and 87, what is the measure of the seventh angle?
xxTIMURxx [149]

Answer:

he seventh angles measure is 103

Step-by-step explanation:

Interior angles = (number of side in the polygon - 2) times 180.

So Heptagon interior angles = (7-2)(180) = 900

To find the missing angles add all the given angles together (122, 153, 168, 105, 162, and 87) = 797.

Now   The measure of the seventh angles = total angles measure - the six given angles,

  The seventh angles measure is 103  

   900 - 797 = 103

7 0
3 years ago
Other questions:
  • Can someone please help me with question 35?
    5·1 answer
  • Help me please ❤️❤️❤️❤️
    10·1 answer
  • 11/12 write fraction in 3 different ways
    7·2 answers
  • Automobile tires can have a symmetric tread or an asymmetric tread. An experiment is to be conducted to determine whether the st
    15·1 answer
  • 11
    15·1 answer
  • emma is building a wall around her garden. it has taken 45 minutes, and she is 75% done. what is the total time it will take Emm
    7·1 answer
  • PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!
    9·2 answers
  • Help please. 10 points to who help me​
    6·1 answer
  • What is the ordered pair of the midpoint of a segment with endpoints at (3, 10) and (7,<br> 20)?
    12·1 answer
  • Sum of 13 and 3 times a number is 31. What is the number?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!