Answer:
Explanation:
Geosynchronous orbit (GSO): Orbits with an altitude of approximately 35,786 km (22,236 mi). Such a satellite would trace an analemma (figure 8) in the sky. Geostationary orbit (GEO): A geosynchronous orbit with an inclination of zero.
Answer:
The submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³
Explanation:
Given;
wet density of soil sample = 2.5 Mg/m³ = 25 kN/m³
Specific gravity of solid particle = 2.7
The dry unit weight of soil;
for undisturbed state, the volume of the soil is;
Submerged effective density is given as;
density of water (ρw) = 2.7 x 25 kN/m³ = 67.5 kN/m³, substitute this in the above equation;
Therefore, the submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³
According to the conservation of momentum. In this situation, the initial momentum is equal to zero.
Since,
p=mv (Momentum)
The initial velocity of the ball = 0 m/s
The initial velocity of the man = 0 m/s
Therefore,
Total Momentum = 0
Law of Conservation of momentum states that the vector sum of the final momenta must be equal to zero which means they will have the same magnitude but in opposite directions.
<span>When the ball is kicked forward along the surface with a speed 15 m/s.
</span>then the momentum will be:
p = 4 x 15 = 60 kgm/s.
Now, the momentum of the man can be calculated as:
p = 60 kgm/s
mv = 60 kgm/s
As,
mass of the man = 80kg
So,
80 × v = 60 kgm/s
v = 60÷80
v = 0.75 m/s
Distance and force.
You need to know how much force was needed and how far it went to calculate how much work was done. The answer is C.
Answer:
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