Answer:
The power dissipated if the three resistors were connected in parallel across the same potential difference is 405 W
Explanation:
Given;
three identical resistors connected in series
let the first resistor = R₁
let the second resistor = R₂
let the third resistor = R₃
Rt = R₁ + R₂ + R₃
Since the resistors are identical, thus, R₁ = R₂ = R₃ = R
Rt = 3R
Power is given as;
P = IV = V² / R
If the 3 identical resistor connection were changed to parallel, then the equivalent resistance in the circuit will be;
Therefore, the power dissipated if the three resistors were connected in parallel across the same potential difference is 405 W
The correct answer from the choices listed above is the first option. The statement that is true would be that c<span>ompound AB has chemical and physical properties that are completely different from those of A and B. They completely different substances with different properties.</span>
Answer:
-4×-2y=14 (1)
-10×+7y=-25 (2)
multiplying eq 1 by 7 and eq 2 by 2 and add eq. 1 and 2
-28×-14y=98
-20×+14y=-50
___________
-28×=48
×=48/-28
×=-12/7
now
-4×-2y=14
-4*-12/7-2y=14
48/7-2y=14
-2y=14-48/7
-2y=(98-48)/7
-2y=50/7
y=-50/14
y=-25/7
Answer;
=15855.40 kg/m^3
Explanation;
Volume (V) of the cylinder = pi x r^2 x h
V = 3.14 x (44/2 x 10^-3)^2 x 41.5 x 10^-3
V = 6.307 x 10^-5 m^3
By density = m/V
mass = 1 kg
density = 1/(6.307 x 10^-5) = 15855.40 kg/m^3
