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just olya [345]
3 years ago
5

Calculate the distance the gecko covers when sprinting from rest to 2 m/s in a time of 1.5 s.

Physics
1 answer:
KIM [24]3 years ago
8 0

Answer:

1.5 m

Explanation:

a = v/t

a = 2/1,5 = 4/3

x = 1/2 a t² + vt + x

x = 1/2 × 4/3 × 9/4 = 3/2 =1.5 m

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Explanation:

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ExtremeBDS [4]

Answer:

B. 14.4 N

Rotational speed (Angular Velocity) = 2

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7 0
3 years ago
Suppose an asteroid orbiting the sun had an orbital period of 7. 5 years. What would its orbital radius be?.
creativ13 [48]

By using the orbital period equation we will find that the orbital radius is r = 4.29*10^11 m

<h3>What is the orbital period?</h3>

This would be the time that a given body does a complete revolution in its orbit.

It can be written as:

T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }

Where:

  • π = 3.14
  • G is the gravitational constant = 6.67*10^(-11) m^3/(kg*s^2)
  • M is the mass of the sun = 1.989*10^30 kg
  • r is the radius, which we want to find.

Rewriting the equation for the radius we get:

T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }\\\\r = \sqrt[3]{ \frac{T^2*G*M}{4*\pi ^2} }

Where T = 7.5 years = 7.5*(3.154*10^7 s) = 2.3655*10^8 s

Replacing the values in the equation we get:

r = \sqrt[3]{ \frac{(2.3655*10^8 s)^2*(6.67*10^{-11} m^3/(kg*s^2))*(1.989*10^{30} kg)}{4*3.14 ^2} } = 4.29*10^{11 }m

So the orbital radius is 4.29*10^11 m

If you want to learn more about orbits, you can read:

brainly.com/question/11996385

7 0
2 years ago
An electron and a proton are each accelerated from rest through a potential difference of 100 V. Afterward, which particle has t
Lena [83]

Explanation:

The De-Broglie wavelength in terms of potential difference is given by:

\lambda=\dfrac{h}{\sqrt{2meV} }

Where,

h is Planck's constant

m is mass of charged particle

V is potential difference

e is the amount of charge

It means that the De-Broglie wavelength is inversely proportional to the mass.

Since, the mass of the proton is more than the mass of the electron. So, the De- Broglie wavelength of the electron is larger than proton.

3 0
3 years ago
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