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Ivanshal [37]
2 years ago
5

Which of these periodic motions are simple harmonic?

Physics
1 answer:
marta [7]2 years ago
4 0

Since the acceleration of the body is directed toward the center of the motion and proportional to its displacement from that point, option a and c are the correct answers of simple harmonic motion

SIMPLE HARMONIC MOTION

Simple Harmonic Motion is the periodic motion of particle or object along a straight line such that the acceleration of the body is directed toward the center of the motion and proportional to its displacement from that point.

Another name for periodic motion is oscillatory motion.

Example are

  • Motion of a simple pendulum.
  • Motion of mass suspended from spring.
  • Motion of loaded tube in a liquid.

A child swinging on a playground swing at angle Ø = 45° will experience back and forth movement which indeed is a simple harmonic motion.

A CD rotating in a player will experience a circular motion and not periodic motion

An oscillating clock pendulum (Ø = 10°) will also experience back and forth motion which is periodic motion and it is simple harmonic motion because it is directed toward a fixed point.

Therefore, option a and c are simple harmonic motion.

Learn more about Simple Harmonic Motion here: brainly.com/question/24646514

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True or false question scientists can predict when an earthquake will occur
Tanya [424]

Answer:

False

Explanation:

Neither the USGS nor any other scientists have ever predicted a major earthquake. USGS scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.

6 0
3 years ago
Three positive charges A, B, and C, and a negative charge D are placed in a line as shown in the diagram. All four charges are o
Irina18 [472]

Answer:

a. q_C experiences the greatest net force and q_B experiences the smallest net force

b. Ratio of the greatest to the smallest net force= 9

Explanation:

<u>Electrostatic Forces </u>

Two point-charges q1 and q2, separated a distance d, exert on each other an electrostatic force of magnitude

\displaystyle F=K\frac{q_1q_2}{d^2}

If the charges have the same sign, they repel each other, for different signed charges, they attract. That gives us the direction of each force in the space.

Let's assume all the charges of the problem have a magnitude q, and between two consecutive charges, the distance is d. The proposed layout is shown it the image.

a.

The net force on qA is the sum of those exerted by qB, qC, and qD. But note qB and qC repel qA and qD attracts it, so the total force on qA is

F_{TA}=-F_B-F_C+F_D

Computing the individual forces we have

\displaystyle F_B=\frac{K\ q_A\ q_B}{d^2}=K\ \frac{q^2}{d^2}

\displaystyle F_C=\frac{K\ q_A\ q_C}{(2d)^2}=\frac{1}{4}\ \ \frac{K\ q^2}{d^2}

\displaystyle F_D=\frac{K\ q_A\ q_D}{(3d)^2}=\frac{1}{9}\ \ \frac{K\ q^2}{d^2}

The total force on qA is:

\displaystyle F_{TA}=\frac{K\ q^2}{d^2}(-1-\frac{1}{4}+\frac{1}{9})

\displaystyle F_{TA}=-\frac{41}{36}\ \frac{K\ q^2}{d^2}

\displaystyle |F_{TA}|=\frac{41}{36}\ \frac{K\ q^2}{d^2}

Charge qA repels qB to the right, qC repels qB to the left, and qD attracts qB to the right, thus

\displaystyle F_{TB}=F_A-F_C+F_D

\displaystyle F_{TB}=\frac{K\ q^2}{d^2}-\frac{K\ q^2}{d^2}+\frac{K\ q^2}{(2d)^2}

\displaystyle F_{TB}=\frac{1}{4}\ \frac{K\ q^2}{d^2}

\displaystyle |F_{TB}|=\frac{1}{4}\ \frac{K\ q^2}{d^2}

Charges qA and qb repel qC to the right, and qD attracts qC to the right, thus

\displaystyle F_{TC}=F_A+F_B+F_D

\displaystyle F_{TC}=\frac{K\ q^2}{(2d)^2}+\frac{K\ q^2}{d^2}+\frac{K\ q^2}{d^2}

\displaystyle F_{TC}=\frac{9}{4}\ \frac{K\ q^2}{d^2}

\displaystyle |F_{TC}|=\frac{9}{4}\ \frac{K\ q^2}{d^2}

Charge qA and qB attract qD to the left, and qC atracts qD to the left, thus

\displaystyle F_{TD}=-F_A-F_B-F_C

\displaystyle F_{TD}=-\frac{K\ q2}{(3d)^2}-\frac{K\ q2}{(2d)^2}-\frac{K\ q2}{d^2}

\displaystyle F_{TD}=-\frac{49}{36}\ \frac{K\ q^2}{d^2}

\displaystyle |F_{TD}|=\frac{49}{36}\ \frac{K\ q^2}{d^2}

Comparing the relative values of all the forces

\displaystyle |F_{TC}|>|F_{TD}|>|F_{TA}|>|F_{TB}|

This means that qc experiences the greatest net force and qB experiences the smallest net force

b.

The ratio of the greatest to the smallest forces is

\displaystyle \frac{|F_{TC}|}{|F_{TB}|}=\frac{\frac{9}{4}}{\frac{1}{4}}=9

5 0
3 years ago
What information is needed to determine the orientation of an orbital?
kolbaska11 [484]

Answer:

The magnetic quantum number (l) determines the orientation of an orbital

Explanation:

The magnetic quantum number of an electron's orbital is the spatial orientation of the electron's orbital

The magnetic quantum number, ml, specifies the orientation and number of orbitals of electrons in a subshell. The value of the magnetic quantum number is dependent on the angular momentum quantum number I with values ranging from -I to +I.

The shape of the electron's orbital is determined by the angular momentum quantum number.

8 0
3 years ago
If I was a scientist and I wanted to measure the intensity of an earthquake I would use
g100num [7]

Answer:

A seismograph

Explanation:

6 0
3 years ago
What causes light to bend when it moves from one transparent medium to another?
DedPeter [7]
Light<span> refracts whenever it </span>travels<span> at an angle into a substance with a </span>different<span>refractive index (optical density). This change of direction is </span>caused<span> by a change in speed. For example, when </span>light travels<span> from air into water, it slows down, causing it to continue to travel at a </span>different<span> angle or direction.</span>
4 0
4 years ago
Read 2 more answers
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