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suter [353]
3 years ago
10

Describe two ways you could demonstrate an acceleration of 2 meters per second squared?

Chemistry
2 answers:
BaLLatris [955]3 years ago
7 0

Answer:

You could do 88 metars  

Explanation:

Elena-2011 [213]3 years ago
6 0
88 meters

hope this helps:)
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Consider the balanced equation below. 4NH3 + 3O2 2N2 + 6H2O What is the mole ratio of NH3 to N2?
vladimir1956 [14]
Is go be 4x=7 so when you see yo thing pick the 2nd one it's go be b
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1. The electronegativities of the period-3 elements are listed on the transparency. Calculate the
Firdavs [7]
The correct answer is c. Please give me brainlest let me know if it’s correct or not thanks bye
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15A.4(a) What is the temperature of a two-level system of energy separation equivalent to 400 cm−1 when the population of the up
maksim [4K]

Answer:

T = 525K    

Explanation:

The temperature of the two-level system can be calculated using the equation of Boltzmann distribution:

\frac{N_{i}}{N} = e^{-\Delta E/kT}  (1)

<em>where Ni: is the number of particles in the state i, N: is the total number of particles, ΔE: is the energy separation between the two levels, k: is the Boltzmann constant, and T: is the temperature of the system </em>         

The energy between the two levels (ΔE) is:

\Delta E = hck    

<em>where h: is the Planck constant, c: is the speed of light and k: is the wavenumber</em>      

\Delta E = 6.63\cdot 10^{-34} J.s \cdot 3\cdot 10^{8}m/s \cdot 4 \cdot 10^{4}m^{-1} = 7.96 \cdot 10^{-21}J  

Solving the equation (1) for T:

T = \frac{-\Delta E}{k \cdot Ln(N_{i}/N)}  

<em>With Ni = N/3 and k = 1.38x10⁻²³ J/K, </em><em>the temperature of the two-level system is:</em><em> </em>

T = \frac{-7.96 \cdot 10^{-21}J}{1.38 \cdot 10^{-23} J/K \cdot Ln(N/3N)} = 525K                                  

I hope it helps you!

3 0
3 years ago
Which structure diagram completes the table of physical structures of the main functional groups? A 6 column table with 1 row. C
erastovalidia [21]

Answer:

B

Explanation:

did it on edge

7 0
2 years ago
How many liters of a 0.5 m sodium hydroxide solution would contain 2 moles of solute?
Klio2033 [76]

Answer:

  • 4 liters

Explanation:

<u>1) Data:</u>

a) M = 0.5 M

<u>Note</u>: since the question is about volume (liters) and moles of solute, the correct unit for the concentration of the hydroxide solution is M (upper case) which is the unit for molarity. Lower case m is used for molality, and you cannot calculate the volume of the solution unless you know some other data, e.g. density of the solution.

b) n = 2

c) V (in liters) = ?

<u>2) Formula:</u>

Molarity is the number of moles of solute per liter of solution:

  • M = n / V (in liters)

<u>3) Solution:</u>

a) Clear V from the formula: V (in liters) = M / n

b) Substitute: V (in liters) =  2 moles /  0.5M  = 4 liters ← answer

7 0
3 years ago
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