Answer: 64.6 mmHg
Explanation:
Given that:
Volume of gas V = 3.47L
(since 1 liter = 1dm3
3.47L = 3.47dm3)
Temperature T = 85.0°C
Convert Celsius to Kelvin
(85.0°C + 273 = 358K)
Pressure P = ?
Number of moles of gas N = 0.100 mole
Note that Molar gas constant R is a constant with a value of 0.0082 ATM dm3 K-1 mol-1
Then, apply ideal gas equation
pV = nRT
p x 3.47dm3 = 0.10 x (0.0082 atm dm3 K-1 mol-1 x 358K)
p x 3.47dm3 = 0.29 atm dm3
p = (0.29 atm dm3 / 3.47 dm3)
p = 0.085 atm
Recall that pressure of the gas is required in mm hg, so convert 0.085 atm to mm Hg
If 1 atm = 760 mm Hg
0.085atm = 0.085 x 760
= 64.6 mm Hg
Thus, the pressure of the gas is 64.6 mm hg
D. To answer this question refer to the periodic table and think logically about it. Adding one proton increases the atomic number so you go along the row to Nitrogen. If you lose one neutron then the atomic mass decreases by 1 so 14-1 is 13.
Answer:
sorry don't know the answer but i really need the points sorry
Explanation:
The ribosomes are the ones delivering the products of the endoplasmic reticulum
Answer:
d- 7.58 L
Explanation:
According to Charles's law, the temperature in Kelvin is proportional to the volume of a dry gas when the pressure is constant.
Mathematically, V1/T1 = V2/ T2
V1= initial volume= 6.6 L
T1= Initial temperature= 115 °C= (115 °C +273)=388K
V2= final volume
T2= final temperature= 173 °C= ( 173 °C+ 273)= 446K
Substitute the values,
V2=( V1 × T2)/ T1
= (6.6×446)/388
= 2943.6/388
= 7.6L
