Initial velocity U = 0
Final velocity V = 32.23 m/s
Explanation:
Given that a coin is dropped from the top of the Tower of Pisa, 53m above the ground.
What is the coin's initial velocity ?
Since the coin is dropped from the tower, the initial velocity U will be equal to zero.
Therefore, U = 0
But the final velocity V will be calculated by using the formula
V^2 = U^2 + 2gH
V^2 = 0 + 2 × 9.8 × 53
V^2 = 1038.8
V = sqrt ( 1038.8)
V = 32.23 m/s
sorry if did not help :(
Answer:
-0.7 m/s
Explanation:
Initial velocity (u)= 2.5 m/s
Acceleleration (a)= -0.8 m/s^2
Time taken (t) = 4 seconds
Hence,
v=u+at [1st Equation of motion]
v=2.5+-0.8*4
v=2.5-3.2
v=-0.7 m/s
Note that the negative sign indicates that the ball has changed direction and rolls downwards with gravity
Viscosity is another type of bulk property defined as a liquid's resistance to flow. When the intermolecular forces of attraction are strong within a liquid, there is a larger viscosity. An example of this phenomenon is imagining a race between two liquids down a windshield.
Answer:
Explanation:
Given that,
Number of turns of coil
N = 50 turns
Initial area of plane
A1 = 0.18 m²
The coil it stretch to a no area in time t = 0.1s
No area implies that the final area is 0, A2 = 0 m²
Constant magnetic field strength
B = 1.51 T
EMF?
EMF is given as
Using far away Lenz law
ε = —N• dΦ/dt
Where Φ = BA
Then,
ε = —N• d(BA)/dt
Since B is constant,
ε = —N•B dA/dt
ε = —N•B (∆A/∆t)
ε = —N•B(A2—A1)/(t2-t1)
ε = —50 × 1.51 (0—0.18)/(0.1—0)
ε =—75.5 × —0.18 / 0.1
ε = 135.9 V
The induced EMF is 135.9V
Fleming’s left hand rule stated that if the index finger points toward magnetic flux, the thumb towards the motion of the conductor, then the middle finger points towards the induced emf.
Since the area lines in the plane, then the induced emf will be out of the page
What it looks to be that you found in A was the "initial"...b/c the question asks:
<span>"how much energy does the electron have 'initially' in the n=4 excited state?" </span>
<span>"final" would be where it 'finally' ends up at, ie. its last stop...as for this question...the 'ground state' as in its lowest energy level. </span>
The answer comes to: <span>−1.36×10^−19 J</span>
You use the same equation for the second part as for part a.
<span>just have to subract the 2 as in the only diff for part 2 is that you use 1squared rather than 4squared & subract "final -initial" & you should get -2.05*10^-18 as your answer. </span>
